Math Problem Statement

Which point would be a solution to the system of linear inequalities shown below?

y, is greater than, minus, 4, x, plus, 6, y, is greater than, one third, x, minus, 7

y>−4x+6y>31​x−7

Answer

Multiple Choice Answers

left parenthesis, 9, comma, minus, 7, right parenthesis(9,−7)

left parenthesis, minus, 12, comma, minus, 2, right parenthesis(−12,−2)

left parenthesis, 12, comma, 1, right parenthesis(12,1)

left parenthesis, minus, 12, comma, minus, 7, right parenthesis(−12,−7)

Solution

To determine which point is a solution to the system of linear inequalities, we need to check each point against the given inequalities:

  1. First inequality: y>4x+6y > -4x + 6
  2. Second inequality: y>13x7y > \frac{1}{3}x - 7

Let's test each of the given points:

1. Point (9,7)(9, -7):

  • First inequality: 7>4(9)+6-7 > -4(9) + 6 simplifies to 7>36+6-7 > -36 + 6 or 7>30-7 > -30 (True)
  • Second inequality: 7>13(9)7-7 > \frac{1}{3}(9) - 7 simplifies to 7>37-7 > 3 - 7 or 7>4-7 > -4 (False)

This point does not satisfy the second inequality, so it is not a solution.

2. Point (12,2)(-12, -2):

  • First inequality: 2>4(12)+6-2 > -4(-12) + 6 simplifies to 2>48+6-2 > 48 + 6 or 2>54-2 > 54 (False)
  • Second inequality: 2>13(12)7-2 > \frac{1}{3}(-12) - 7 simplifies to 2>47-2 > -4 - 7 or 2>11-2 > -11 (True)

This point does not satisfy the first inequality, so it is not a solution.

3. Point (12,1)(12, 1):

  • First inequality: 1>4(12)+61 > -4(12) + 6 simplifies to 1>48+61 > -48 + 6 or 1>421 > -42 (True)
  • Second inequality: 1>13(12)71 > \frac{1}{3}(12) - 7 simplifies to 1>471 > 4 - 7 or 1>31 > -3 (True)

This point satisfies both inequalities.

4. Point (12,7)(-12, -7):

  • First inequality: 7>4(12)+6-7 > -4(-12) + 6 simplifies to 7>48+6-7 > 48 + 6 or 7>54-7 > 54 (False)
  • Second inequality: 7>13(12)7-7 > \frac{1}{3}(-12) - 7 simplifies to 7>47-7 > -4 - 7 or 7>11-7 > -11 (True)

This point does not satisfy the first inequality, so it is not a solution.

Conclusion:

The only point that satisfies both inequalities is (12,1)(12, 1).

Answer: (12,1)(12, 1)

Would you like more details or have any questions about this?

Here are five related questions to consider:

  1. How do you graph the boundary lines for linear inequalities?
  2. What does the solution region of a system of linear inequalities represent?
  3. How can you check if a point is on the boundary line of an inequality?
  4. What happens to the solution region when you change the inequality sign (e.g., from >> to \geq)?
  5. How do you solve a system of linear inequalities with more than two inequalities?

Tip: When checking if a point satisfies an inequality, substitute the point into the inequality and simplify. If the resulting statement is true for both inequalities, the point is a solution to the system.

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Math Problem Analysis

Mathematical Concepts

Linear Inequalities
Graphing Inequalities
Solution of Inequalities

Formulas

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Theorems

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Suitable Grade Level

High School