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To solve this problem, we need to calculate the mass of sodium nitrate (\( \text{NaNO}_3 \)) in kilograms based on the given data.

### Given:
- Volume of solution added: \( 575.0 \, \text{mL} \)
- Concentration of sodium nitrate: \( 31.9 \, \text{g/dL} \)

#### Step 1: Convert \( 575.0 \, \text{mL} \) to dL
Since \( 1 \, \text{dL} = 100 \, \text{mL} \), we can convert the volume of the solution:
\[
575.0 \, \text{mL} = \frac{575.0}{100} \, \text{dL} = 5.750 \, \text{dL}
\]

#### Step 2: Calculate the mass of sodium nitrate in grams
Using the concentration \( 31.9 \, \text{g/dL} \), we multiply by the volume in dL to find the mass:
\[
\text{mass in grams} = 31.9 \, \text{g/dL} \times 5.750 \, \text{dL} = 183.425 \, \text{g}
\]

#### Step 3: Convert grams to kilograms
Since \( 1 \, \text{kg} = 1000 \, \text{g} \), we divide the mass in grams by 1000:
\[
\text{mass in kg} = \frac{183.425}{1000} = 0.183425 \, \text{kg}
\]

### Final Answer:
The mass of sodium nitrate added to the flask is approximately **0.183 kg** (rounded to 3 significant figures, based on the given data).

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Would you like further clarification on any part of this solution, or more details? 

Here are 5 related questions:
1. How is significant figure rounding applied in chemistry calculations?
2. Why is concentration measured in g/dL in this context?
3. How would you approach this if the volume was given in liters instead of milliliters?
4. What is the purpose of converting grams to kilograms in this problem?
5. Can you describe the relationship between molarity and mass in solution-based problems?

**Tip:** Always ensure unit conversions are handled carefully in chemistry problems to avoid calculation errors.

A chemist adds 575.0 mL of a 31.9 g/dL sodium nitrate (NaNO3) solution to a flask. Calculate the mass in kilograms of sodium nitrate the chemist has added to the flask.

Calculate the mass of sodium nitrate (NaNO3) added to a flask based on a given volume of 575.0 mL and a concentration of 31.9 g/dL. The detailed step-by-step solution includes unit conversion and multiplication, making this problem suitable for high school students (Grades 10-12).

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