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To solve this problem, we need to calculate the volume of a 1.74 M sodium chloride (NaCl) solution containing 125 grams of NaCl. The formula for molarity (M) is given by:

\[
M = \frac{\text{moles of solute}}{\text{liters of solution}}
\]

We can rearrange the formula to solve for the volume in liters:

\[
\text{Volume (L)} = \frac{\text{moles of solute}}{M}
\]

### Steps:

1. **Calculate the moles of NaCl**:
   We are given 125 g of NaCl, and the molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl):
   
   - Molar mass of Na = 22.99 g/mol
   - Molar mass of Cl = 35.45 g/mol
   
   Therefore, the molar mass of NaCl is:
   \[
   \text{Molar mass of NaCl} = 22.99 + 35.45 = 58.44 \, \text{g/mol}
   \]
   
   Now, we can calculate the moles of NaCl:
   \[
   \text{moles of NaCl} = \frac{125 \, \text{g}}{58.44 \, \text{g/mol}} \approx 2.14 \, \text{mol}
   \]

2. **Calculate the volume of the solution**:
   Using the molarity formula and the given molarity of 1.74 M, we can solve for the volume:
   \[
   \text{Volume (L)} = \frac{2.14 \, \text{mol}}{1.74 \, \text{M}} \approx 1.23 \, \text{L}
   \]

Therefore, the volume of the solution is approximately **1.23 liters**.

Would you like further clarification or details on any part of this solution?

Here are 5 related questions:
1. What is the significance of molarity in chemical solutions?
2. How would you adjust the calculation if the mass of NaCl were different?
3. Can you calculate the volume for a solution with a different molarity?
4. How does the molar mass of a substance affect the number of moles?
5. What would happen if the solution were diluted?

**Tip**: Always ensure to keep the correct number of significant figures throughout the calculation for accurate results.

Calculate the volume in liters of a 1.74 M sodium chloride solution that contains 125 g of sodium chloride (NaCl). Be sure your answer has the correct number of significant digits.

Learn how to calculate the volume of a 1.74 M sodium chloride solution that contains 125 g of NaCl. This problem covers solution concentration, molarity, and significant figures, suitable for high school chemistry students in Grades 10-12.

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