Math Problem Statement

what is the smallest non zero whole number that is divisible by both 176 and 342

Solution

To find the smallest non-zero whole number divisible by both 176 and 342, we need to calculate the least common multiple (LCM) of these two numbers.

The LCM can be found using the formula:

LCM(a,b)=a×bGCD(a,b)\text{LCM}(a, b) = \frac{a \times b}{\text{GCD}(a, b)}

Where GCD is the greatest common divisor.

Step 1: Find the GCD of 176 and 342

  • Find the prime factorizations of 176 and 342:
    • 176=24×11176 = 2^4 \times 11
    • 342=2×32×19342 = 2 \times 3^2 \times 19

The only common factor is 212^1.

So, the GCD(176, 342) = 2.

Step 2: Calculate the LCM

Now we apply the LCM formula:

LCM(176,342)=176×3422\text{LCM}(176, 342) = \frac{176 \times 342}{2}

176×342=60192176 \times 342 = 60192 601922=30096\frac{60192}{2} = 30096

Thus, the smallest non-zero whole number divisible by both 176 and 342 is 30,096.

Would you like more details or have any questions?

Here are 5 related questions:

  1. What is the difference between LCM and GCD?
  2. How can the Euclidean algorithm be used to find the GCD?
  3. Can you explain prime factorization in more detail?
  4. How is the LCM useful in solving real-world problems?
  5. What is the process to find the LCM of more than two numbers?

Tip: Always double-check calculations, especially with prime factorizations, to avoid small mistakes in larger computations!

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Math Problem Analysis

Mathematical Concepts

Number Theory
Greatest Common Divisor (GCD)
Least Common Multiple (LCM)
Prime Factorization

Formulas

LCM(a, b) = (a × b) / GCD(a, b)

Theorems

Euclidean algorithm for GCD

Suitable Grade Level

Grades 9-12