The equation you provided is in slope-intercept form, which is $y = mx + b$, where:

• $m$ is the slope of the line.
• $b$ is the y-intercept (the point where the line crosses the y-axis).

For the equation $y = \frac{1}{2}x + 2$, we can identify:

• The slope $m = \frac{1}{2}$.
• The y-intercept $b = 2$.

This means the line rises by 1 unit for every 2 units it moves to the right (since the slope is $\frac{1}{2}$), and it crosses the y-axis at $y = 2$.

Would you like to explore more details, such as graphing the equation or finding specific points on the line?

Related Questions:

1. How do you graph the equation $y = \frac{1}{2}x + 2$?
2. What happens to the graph if the slope changes to $m = -\frac{1}{2}$?
3. How can you find the x-intercept of this line?
4. What does the slope $\frac{1}{2}$ represent in real-life scenarios?
5. How would the equation change if the y-intercept were 0?

Tip:

To graph a line from slope-intercept form, start by plotting the y-intercept and then use the slope to find another point. For $y = \frac{1}{2}x + 2$, start at $(0, 2)$, then move up 1 unit and right 2 units to find the next point.