To find the slope-intercept form of the line, we use the equation:

$y = mx + b$

where:

• $m$ is the slope, and
• $b$ is the y-intercept.

In this case, the slope $m = 0$, so the equation simplifies to:

$y = 0x + b$

which becomes:

$y = b$

Since the line passes through the point $(-3, -1)$, we substitute these values into the equation to find $b$:

$-1 = b$

Thus, the equation of the line is:

$y = -1$

This is a horizontal line with a constant value of $y = -1$.

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Would you like further details or have any questions? Here are 5 related questions to explore further:

1. How do you find the slope between two given points?
2. What is the equation of a vertical line passing through a given point?
3. Can you explain how the slope affects the orientation of a line?
4. What does it mean if the slope is undefined?
5. How do you convert a general linear equation into slope-intercept form?

Tip: A line with a slope of zero is always horizontal, meaning it does not rise or fall, but stays constant along the y-axis.