Math Problem Statement

Sketch the curve by eliminating the parameter, and indicate the direction of increasing t. x=3t−4,y=6t+2.

Solution

To sketch the curve defined by the parametric equations x=3t4x = 3t - 4 and y=6t+2y = 6t + 2, we need to eliminate the parameter tt and express yy as a function of xx.

Step 1: Solve for tt in terms of xx

From the equation: x=3t4x = 3t - 4 we can solve for tt: t=x+43t = \frac{x + 4}{3}

Step 2: Substitute tt in the equation for yy

Now, substitute t=x+43t = \frac{x + 4}{3} into the equation y=6t+2y = 6t + 2: y=6(x+43)+2y = 6\left(\frac{x + 4}{3}\right) + 2 Simplify this: y=2(x+4)+2y = 2(x + 4) + 2 y=2x+8+2y = 2x + 8 + 2 y=2x+10y = 2x + 10

So, the Cartesian equation of the curve is: y=2x+10y = 2x + 10

This equation represents a straight line with a slope of 22 and a y-intercept of 1010.

Step 3: Determine the direction of increasing tt

To find the direction of increasing tt, we can analyze the behavior of xx and yy as tt increases:

  • As tt increases, x=3t4x = 3t - 4 also increases.
  • Similarly, y=6t+2y = 6t + 2 increases as tt increases.

Thus, the direction of increasing tt is from left to right along the line y=2x+10y = 2x + 10.

Summary

The sketch of the curve will be a straight line given by y=2x+10y = 2x + 10, with the direction of increasing tt moving from left to right along the line.

Would you like to see more details on graphing this line, or do you have any questions?


  1. How would we approach this if the equations were nonlinear?
  2. How do we handle cases where eliminating the parameter isn't straightforward?
  3. What if the direction of tt were reversed?
  4. How can we check our result for parametric equations using a graphing calculator?
  5. What are alternative methods for sketching parametric curves?

Tip: When converting parametric equations, always check if simplifying assumptions (like linearity) apply to make the process quicker.

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Math Problem Analysis

Mathematical Concepts

Parametric Equations
Cartesian Equations
Linear Functions

Formulas

x = 3t - 4
y = 6t + 2
y = mx + c (slope-intercept form of a linear equation)

Theorems

Slope-Intercept Form of a Line

Suitable Grade Level

Grades 9-12