Math Problem Statement

How to sketch ay(x^2-\frac{1}{3} y^2)=constant in the first quadrant?

Solution

To sketch the equation ay(x213y2)=Cay(x^2 - \frac{1}{3}y^2) = C in the first quadrant, where aa and CC are constants, we need to follow several steps. Here's the detailed process:

Step 1: Express the equation in a more convenient form

Start by rewriting the equation for clarity: ay(x213y2)=Ca y \left( x^2 - \frac{1}{3} y^2 \right) = C Now, solve for yy: y(x213y2)=Cay \left( x^2 - \frac{1}{3} y^2 \right) = \frac{C}{a} This is a non-linear equation, so let's attempt to solve it for specific values of xx and yy.

Step 2: Analyze the equation for different values of xx

When x=0x = 0:

Substitute x=0x = 0 into the equation: ay(0213y2)=Ca y \left( 0^2 - \frac{1}{3} y^2 \right) = C This simplifies to: a3y3=C- \frac{a}{3} y^3 = C Solve for yy: y3=3Cay^3 = -\frac{3C}{a} Thus, we have y=(3Ca)1/3y = \left( -\frac{3C}{a} \right)^{1/3}.

When y=0y = 0:

Substitute y=0y = 0 into the equation: a0(x21302)=Ca \cdot 0 \cdot \left( x^2 - \frac{1}{3} \cdot 0^2 \right) = C This simplifies to 0=C0 = C, which implies C=0C = 0.

Step 3: Explore the general form for y>0y > 0 and x>0x > 0

Now let's express yy in terms of xx. From the original equation: ay(x213y2)=Ca y \left( x^2 - \frac{1}{3} y^2 \right) = C Solve for yy: y=Ca(x213y2)y = \frac{C}{a \left( x^2 - \frac{1}{3} y^2 \right)} This equation is implicit, and finding an explicit solution for yy in terms of xx is not trivial without further assumptions. However, you can still sketch the curve numerically or graphically by considering specific values for CC and aa.

Step 4: General shape and behavior

  • In the first quadrant, both x>0x > 0 and y>0y > 0, and the equation describes a relationship between xx and yy that is implicitly non-linear.
  • As xx increases, the term x2x^2 dominates, and the behavior of the curve will tend to behave like a hyperbola or some similar non-linear shape.

Step 5: Sketching the curve

You can start sketching the curve by:

  1. Plotting the asymptotes (behavior as xx or yy approach large values).
  2. Using specific values for xx and yy to plot points.
  3. Connecting these points to form a curve.

In the first quadrant, the curve would start near the origin (but not pass through it if C0C \neq 0), then curve upwards and to the right, potentially approaching asymptotic behavior based on the form of the equation.


Additional Insight:

Would you like a more detailed solution using specific values for aa and CC, or would you prefer to explore the asymptotic behavior or further graphing techniques?

5 Related Questions:

  1. How does changing the value of CC affect the shape of the curve?
  2. What happens to the graph as aa increases?
  3. Can you find the equation's asymptotes?
  4. What is the behavior of the curve when yy approaches large values?
  5. How does this equation compare to a general hyperbola?

Tip: A good way to understand implicit relationships between variables is to solve for one variable (e.g., yy) numerically for specific values of the other (e.g., xx), especially if the algebraic manipulation is complex.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Implicit Equations
Graphing Non-linear Equations
Asymptotic Behavior

Formulas

ay(x^2 - \frac{1}{3} y^2) = C
y = \left( -\frac{3C}{a} \right)^{1/3}

Theorems

Implicit Function Theorem

Suitable Grade Level

Grades 11-12