Math Problem Statement

Sketch the graph of Y= x^(2) - 4x + 4

Solution

To sketch the graph of the function y=x24x+4y = x^2 - 4x + 4, let's analyze its key features, such as the vertex, axis of symmetry, intercepts, and overall shape.

Step-by-Step Analysis

  1. Identify the Type of Function:
    The function y=x24x+4y = x^2 - 4x + 4 is a quadratic function. Its general form is y=ax2+bx+cy = ax^2 + bx + c, where a=1a = 1, b=4b = -4, and c=4c = 4.

  2. Determine the Shape:
    Since a=1>0a = 1 > 0, the parabola opens upwards.

  3. Find the Vertex:
    The vertex form of a parabola is given by x=b2ax = -\frac{b}{2a}. For this function: x=42×1=42=2.x = -\frac{-4}{2 \times 1} = \frac{4}{2} = 2. To find the y-coordinate of the vertex, substitute x=2x = 2 into the function: y=(2)24(2)+4=48+4=0.y = (2)^2 - 4(2) + 4 = 4 - 8 + 4 = 0. So, the vertex is at (2,0)(2, 0).

  4. Axis of Symmetry:
    The axis of symmetry for a parabola y=ax2+bx+cy = ax^2 + bx + c is the vertical line passing through the vertex. In this case, it is x=2x = 2.

  5. Find the Y-intercept:
    The y-intercept occurs when x=0x = 0: y=024(0)+4=4.y = 0^2 - 4(0) + 4 = 4. So, the y-intercept is at (0,4)(0, 4).

  6. Find the X-intercepts:
    The x-intercepts occur when y=0y = 0. We solve the quadratic equation: x24x+4=0.x^2 - 4x + 4 = 0. Factor the quadratic: (x2)(x2)=0.(x - 2)(x - 2) = 0. So, x=2x = 2. This confirms that there is a double root at x=2x = 2. The parabola touches the x-axis at (2,0)(2, 0) but does not cross it.

  7. Sketch the Graph:

    • Plot the vertex at (2,0)(2, 0).
    • The parabola opens upwards.
    • The axis of symmetry is the vertical line x=2x = 2.
    • Plot the y-intercept at (0,4)(0, 4).
    • Since there is a double root at x=2x = 2, the graph just touches the x-axis at this point.

Graph of the Function

Based on the analysis above, the graph is a parabola that touches the x-axis at (2,0)(2, 0) and has a vertex at the same point. It opens upwards and has a y-intercept at (0,4)(0, 4).

If you'd like a visual representation, here is a sketch of the graph:

  y
  |
  |               *
  |             *   
  |          *     
  |       *   
  |     *   
  |  *        
--+------------------ x
  |     *        
  |       *        
  |          *        
  |             *   
  |               *
  |

Would you like more details on any step, or have any specific questions?

Related Questions:

  1. How would the graph change if the equation were y=x24x+5y = x^2 - 4x + 5?
  2. What are the properties of a quadratic function?
  3. How do you find the vertex of a quadratic function in standard form?
  4. What is the significance of the axis of symmetry in a parabola?
  5. How does the value of aa affect the direction and width of a parabola?

Tip: The vertex form of a quadratic function, y=a(xh)2+ky = a(x-h)^2 + k, makes it easy to identify the vertex and direction of the parabola.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Vertex Form
Axis of Symmetry
Intercepts

Formulas

Vertex form of a quadratic function
Quadratic formula

Theorems

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Suitable Grade Level

Grades 7-9