Math Problem Statement

Use the graph of f to sketch the graph of f '.

The x y-coordinate plane is given. The curve enters the window in the second quadrant, goes down and right becoming less steep, changes direction at the origin, goes up and right becoming more steep, passes through the approximate point (1, 0.67), goes up and right becoming less steep, changes direction at the approximate point (2, 1.33), goes down and right becoming more steep, crosses the x-axis at x = 3, and exits the window in the fourth quadrant.

The x y-coordinate plane is given. The curve enters the window in the second quadrant, goes down and right becoming less steep, crosses the x-axis at the origin, changes direction at the point (1, −1), goes up and right becoming more steep, crosses the x-axis at x = 2, and exits the window in the first quadrant.

The x y-coordinate plane is given. The line enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 2, crosses the x-axis at x = 2, and exits the window in the fourth quadrant.

The x y-coordinate plane is given. The line enters the window in the third quadrant, goes up and right, crosses the x-axis at the origin, passes through the point (1, 1), and exits the window in the first quadrant.

The x y-coordinate plane is given. The curve enters the window in the third quadrant, goes up and right becoming less steep, crosses the x-axis at the origin, changes direction at the point (1, 1), goes down and right becoming more steep, crosses the x-axis at x = 2, and exits the window in the fourth quadrant.

(a) Find the open intervals on which f '(x) is positive. (Enter your answer using interval notation.)

Describe the corresponding behavior of f.

f is increasing. f is decreasing. f is concave upward. f is concave downward. (b) Find the open intervals on which f '(x) is negative. (Enter your answer using interval notation.)

Describe the corresponding behavior of f.

f is increasing. f is decreasing. f is concave upward. f is concave downward. (c) Find the open intervals on which f ' is increasing. (Enter your answer using interval notation.)

Describe the corresponding behavior of f.

f is increasing. f is decreasing. f is concave upward. f is concave downward. (d) Find the open intervals on which f ' is decreasing. (Enter your answer using interval notation.)

Describe the corresponding behavior of f.

f is increasing. f is decreasing. f is concave upward. f is concave downward.

Solution

Let’s work through the analysis of ff and its derivative ff' systematically based on the given graph and properties.

(a) Open intervals on which f(x)>0f'(x) > 0

f(x)>0f'(x) > 0 means the slope of ff is positive, which corresponds to ff increasing.

  • From the description:
    • ff is increasing on (0,2)(0, 2) (positive slope between turning points at x=0x = 0 and x=2x = 2).
    • Therefore, f(x)>0f'(x) > 0 on (0,2)(0, 2).

Behavior of ff:

  • On (0,2)(0, 2), ff is increasing.

(b) Open intervals on which f(x)<0f'(x) < 0

f(x)<0f'(x) < 0 means the slope of ff is negative, which corresponds to ff decreasing.

  • From the description:
    • ff is decreasing on (,0)(2,)(-\infty, 0) \cup (2, \infty).
    • Therefore, f(x)<0f'(x) < 0 on (,0)(2,)(-\infty, 0) \cup (2, \infty).

Behavior of ff:

  • On (,0)(2,)(-\infty, 0) \cup (2, \infty), ff is decreasing.

(c) Open intervals on which f(x)f'(x) is increasing

f(x)f'(x) is increasing where the concavity of ff is upward (slopes of ff are becoming steeper in the positive or negative direction).

  • From the description:
    • f(x)f'(x) is increasing on (,1)(-\infty, 1) because ff transitions from steep negative slope to steep positive slope (concave up).
    • Therefore, f(x)f'(x) is increasing on (,1)(-\infty, 1).

Behavior of ff:

  • On (,1)(-\infty, 1), ff is concave upward.

(d) Open intervals on which f(x)f'(x) is decreasing

f(x)f'(x) is decreasing where the concavity of ff is downward (slopes of ff are becoming less steep in the positive or negative direction).

  • From the description:
    • f(x)f'(x) is decreasing on (1,)(1, \infty) because ff transitions from steep positive slope to steep negative slope (concave down).
    • Therefore, f(x)f'(x) is decreasing on (1,)(1, \infty).

Behavior of ff:

  • On (1,)(1, \infty), ff is concave downward.

Final Answers:

(a) Intervals where f(x)>0f'(x) > 0:

  • (0,2)(0, 2)
  • Behavior of ff: ff is increasing.

(b) Intervals where f(x)<0f'(x) < 0:

  • (,0)(2,)(-\infty, 0) \cup (2, \infty)
  • Behavior of ff: ff is decreasing.

(c) Intervals where f(x)f'(x) is increasing:

  • (,1)(-\infty, 1)
  • Behavior of ff: ff is concave upward.

(d) Intervals where f(x)f'(x) is decreasing:

  • (1,)(1, \infty)
  • Behavior of ff: ff is concave downward.

Would you like a visual explanation or further clarification?
Here are 5 questions to expand on this:

  1. What is the significance of f(x)f''(x) in understanding f(x)f'(x)?
  2. How does the second derivative relate to intervals of concavity for ff?
  3. Can you derive exact turning points using specific slope values from the graph?
  4. How can you sketch ff' based on the features of ff?
  5. What happens at points of inflection where f(x)=0f''(x) = 0?

Tip: When sketching ff', look for changes in slope direction (zero crossings and maximum/minimum slopes) to pinpoint its shape.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Differentiation
Increasing and Decreasing Intervals
Concavity

Formulas

f' > 0 indicates f is increasing
f' < 0 indicates f is decreasing
f'' > 0 indicates concave upward
f'' < 0 indicates concave downward

Theorems

First Derivative Test
Second Derivative Test

Suitable Grade Level

Grades 11-12