https://file.aiquickdraw.com/mathbot/file/1727455207239ls5y3zzb.jpg

The problem you provided states:

- The temperature over a day can be modeled as a sinusoidal function.
- The high temperature is 81°F.
- The low temperature is 59°F, and this low occurs at 5 AM.
- \( t \) represents the number of hours since midnight.

We are tasked with finding an equation for the temperature, \( D(t) \), in terms of \( t \).

### Step-by-Step Solution:

#### 1. General Sinusoidal Function:
A sinusoidal function modeling temperature can be written as:
\[
D(t) = A \sin(B(t - C)) + D_0
\]
where:
- \( A \) is the amplitude,
- \( B \) affects the period (since temperature repeats every 24 hours, the period is 24),
- \( C \) is the horizontal shift (the time at which the minimum or maximum occurs),
- \( D_0 \) is the vertical shift (midline of the sinusoid).

#### 2. Finding Amplitude \( A \):
The amplitude \( A \) is half the difference between the maximum and minimum temperatures:
\[
A = \frac{81 - 59}{2} = 11
\]

#### 3. Finding the Vertical Shift \( D_0 \):
The vertical shift \( D_0 \) is the average of the maximum and minimum temperatures:
\[
D_0 = \frac{81 + 59}{2} = 70
\]

#### 4. Determining the Period:
Since temperature repeats every 24 hours, the period \( T \) is 24 hours. The formula relating \( B \) to the period is:
\[
B = \frac{2\pi}{T} = \frac{2\pi}{24} = \frac{\pi}{12}
\]

#### 5. Horizontal Shift \( C \):
The low temperature occurs at 5 AM, which corresponds to a minimum point on the sinusoidal curve. A sine function normally has its minimum at \( \frac{3\pi}{2} \), but since the low temperature occurs at \( t = 5 \), the function is shifted horizontally by 5 hours. Therefore, \( C = 5 \).

#### 6. Complete Equation:
Putting everything together, the equation for \( D(t) \) becomes:
\[
D(t) = 11 \sin\left(\frac{\pi}{12}(t - 5)\right) + 70
\]

### Final Equation:
\[
D(t) = 11 \sin\left(\frac{\pi}{12}(t - 5)\right) + 70
\]

This is the sinusoidal function modeling the temperature in terms of \( t \), the number of hours since midnight.

Would you like more details on any of the steps, or have any further questions?

---

Here are 5 related questions to deepen your understanding:
1. How would the equation change if the low temperature occurred at 3 AM instead of 5 AM?
2. What would happen to the sinusoidal model if the high temperature was lower, say 75°F?
3. How would you modify the equation if the period of the temperature cycle was 12 hours instead of 24?
4. What is the temperature at 12 PM (noon) according to this model?
5. How would the model change if the temperature variation was smaller, say between 70°F and 60°F?

**Tip**: When working with sinusoidal functions, always identify the maximum, minimum, period, and phase shift carefully, as these will affect the shape and position of the graph.

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature for the day is 81 degrees and the low temperature of 59 degrees occurs at 5 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D(t), in terms of t.

Learn how to model the daily temperature as a sinusoidal function with a high of 81°F and a low of 59°F occurring at 5 AM. Explore key concepts like amplitude, period, phase shift, and vertical shift in trigonometry, suitable for students in Grades 10-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation