In Quadrant II, sine is positive and cosine is negative. We can relate sine and cosine using the Pythagorean identity:

$\sin^2(t) + \cos^2(t) = 1$

Solving for $\sin(t)$:

$\sin(t) = \sqrt{1 - \cos^2(t)}$

Since $\sin(t)$ is positive in Quadrant II, the expression for $\sin(t)$ in terms of $\cos(t)$ is:

$\sin(t) = \sqrt{1 - \cos^2(t)}$

Would you like more details or have any questions?

Here are 5 related questions for practice:

1. What is the expression for $\cos(t)$ in terms of $\sin(t)$ in Quadrant II?
2. How does the Pythagorean identity relate sine and cosine?
3. What is the value of $\tan(t)$ in terms of $\sin(t)$ and $\cos(t)$?
4. What changes for sine and cosine in Quadrant III?
5. How do the signs of trigonometric functions vary across all four quadrants?

Tip: Always consider the signs of trigonometric functions in each quadrant.