Math Problem Statement

Write a positive sin equation of a function what has a maxium at (pi/4,5) and minimum point at (pi/2,1)

Solution

To create a positive sine equation with the given characteristics, we need to determine the amplitude, period, phase shift, and vertical shift. Here's how we break it down:

Key information:

  • Maximum at (π/4, 5): This tells us the maximum value of the function is 5.
  • Minimum at (π/2, 1): This tells us the minimum value is 1.

Step-by-step process:

  1. Amplitude (A):

    • The amplitude is half the distance between the maximum and minimum values: A=512=2A = \frac{5 - 1}{2} = 2
  2. Vertical Shift (D):

    • The vertical shift is the average of the maximum and minimum values: D=5+12=3D = \frac{5 + 1}{2} = 3 This means the sine function oscillates around 3.
  3. Period (T):

    • The sine wave completes a full cycle between maximum and minimum points. The distance between the maximum at π/4\pi/4 and minimum at π/2\pi/2 is π/2π/4=π/4\pi/2 - \pi/4 = \pi/4.
    • Since this distance represents half a period (from maximum to minimum), the full period TT is: T=2×π4=π2T = 2 \times \frac{\pi}{4} = \frac{\pi}{2}
    • The period of a sine function is given by T=2πBT = \frac{2\pi}{B}, so: 2πB=π2    B=4\frac{2\pi}{B} = \frac{\pi}{2} \implies B = 4
  4. Phase Shift (C):

    • Since the maximum occurs at x=π/4x = \pi/4, the sine function has been shifted horizontally by π/4\pi/4. For a sine function of the form sin(B(xC))\sin(B(x - C)), C=π/4C = \pi/4.

Putting it all together:

The general form of a sine function is: y=Asin(B(xC))+Dy = A \sin(B(x - C)) + D Substituting the values we found: y=2sin(4(xπ4))+3y = 2 \sin(4(x - \frac{\pi}{4})) + 3

This is the equation of the sine function that has a maximum at (π/4,5)(\pi/4, 5) and a minimum at (π/2,1)(\pi/2, 1).

Would you like further details on any part of this process?

Related Questions:

  1. What is the phase shift of the sine function in more complex transformations?
  2. How would the function change if the maximum were at x=π/2x = \pi/2 instead?
  3. How does changing the amplitude affect the maximum and minimum values?
  4. What would happen if we used a cosine function instead of a sine function?
  5. How can you derive the equation if you are given a different period and phase shift?

Tip:

Always remember that the amplitude and vertical shift affect the function's range, while the period and phase shift influence its horizontal behavior.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Sine Function
Amplitude
Phase Shift
Period

Formulas

Amplitude = (Max - Min) / 2
Vertical Shift = (Max + Min) / 2
Period = 2π / B
General Sine Function: y = A sin(B(x - C)) + D

Theorems

Trigonometric Properties of Sine Functions

Suitable Grade Level

Grades 10-12