Math Problem Statement

Use trigonometric identities to transform the left side of the equation into the right side (0 < 𝜃 < 𝜋/2). tan 𝛽 + cot 𝛽 tan 𝛽

tan 𝛽 tan 𝛽 + cot 𝛽 tan 𝛽

Solution

We are given the equation:

tanβ+cotβtanβ=tanβtanβ+cotβtanβ\frac{\tan \beta + \cot \beta}{\tan \beta} = \frac{\tan \beta}{\tan \beta} + \frac{\cot \beta}{\tan \beta}

To transform the left-hand side into the right-hand side, let's break it down step by step using trigonometric identities.

Step 1: Rewrite the left-hand side

The left-hand side is:

tanβ+cotβtanβ\frac{\tan \beta + \cot \beta}{\tan \beta}

Recall that cotβ=1tanβ\cot \beta = \frac{1}{\tan \beta}. Substituting this in:

tanβ+1tanβtanβ\frac{\tan \beta + \frac{1}{\tan \beta}}{\tan \beta}

Step 2: Combine terms in the numerator

To combine the terms in the numerator, let's rewrite them as a single fraction:

tan2β+1tanβ\frac{\tan^2 \beta + 1}{\tan \beta}

So the left-hand side becomes:

tan2β+1tanβtanβ=tan2β+1tan2β\frac{\frac{\tan^2 \beta + 1}{\tan \beta}}{\tan \beta} = \frac{\tan^2 \beta + 1}{\tan^2 \beta}

Step 3: Simplify the right-hand side

Now, let's simplify the right-hand side, which is:

tanβtanβ+cotβtanβ\frac{\tan \beta}{\tan \beta} + \frac{\cot \beta}{\tan \beta}

The first term simplifies to 1:

1+cotβtanβ1 + \frac{\cot \beta}{\tan \beta}

Since cotβ=1tanβ\cot \beta = \frac{1}{\tan \beta}, the second term becomes:

1+1tanβtanβ=1+1tan2β1 + \frac{\frac{1}{\tan \beta}}{\tan \beta} = 1 + \frac{1}{\tan^2 \beta}

Step 4: Compare the expressions

Now we have:

  • Left-hand side: tan2β+1tan2β\frac{\tan^2 \beta + 1}{\tan^2 \beta}
  • Right-hand side: 1+1tan2β1 + \frac{1}{\tan^2 \beta}

Both expressions are identical, so the transformation is complete.

Thus, the equation holds:

tanβ+cotβtanβ=tanβtanβ+cotβtanβ\frac{\tan \beta + \cot \beta}{\tan \beta} = \frac{\tan \beta}{\tan \beta} + \frac{\cot \beta}{\tan \beta}

Would you like more details or have any questions? Here are some related questions to deepen your understanding:

  1. How do trigonometric identities like cotβ=1tanβ\cot \beta = \frac{1}{\tan \beta} help in simplifying equations?
  2. What is the significance of the interval 0<β<π20 < \beta < \frac{\pi}{2} for trigonometric functions?
  3. Can this equation be transformed using a different set of trigonometric identities?
  4. How would the equation change if you replaced tanβ\tan \beta with sinβ/cosβ\sin \beta / \cos \beta?
  5. What other identities could be useful in simplifying similar expressions?

Tip: Familiarizing yourself with the fundamental trigonometric identities can help simplify a wide range of complex trigonometric expressions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities

Formulas

cot(𝛽) = 1 / tan(𝛽)
tan(𝛽)^2 + 1 = sec(𝛽)^2

Theorems

Basic Trigonometric Identities

Suitable Grade Level

Grades 10-12