Math Problem Statement

secx-tanx(sinx)

Solution

The given mathematical expression is:

secxtanxsinx\sec x - \tan x \sin x

Step 1: Express in Terms of Sine and Cosine

We use the trigonometric identities:

  • secx=1cosx\sec x = \frac{1}{\cos x}
  • tanx=sinxcosx\tan x = \frac{\sin x}{\cos x}

Rewriting the given expression:

1cosx(sinxcosxsinx)\frac{1}{\cos x} - \left( \frac{\sin x}{\cos x} \cdot \sin x \right)

Step 2: Simplify the Expression

1cosxsin2xcosx\frac{1}{\cos x} - \frac{\sin^2 x}{\cos x}

Since both terms have a common denominator cosx\cos x, we combine them:

1sin2xcosx\frac{1 - \sin^2 x}{\cos x}

Step 3: Apply the Pythagorean Identity

From the identity:

sin2x+cos2x=1\sin^2 x + \cos^2 x = 1

We replace 1sin2x1 - \sin^2 x with cos2x\cos^2 x:

cos2xcosx\frac{\cos^2 x}{\cos x}

Step 4: Final Simplification

cosx\cos x

Final Answer:

cosx\cos x


Would you like a detailed explanation of any step?

Related Questions:

  1. What are the fundamental trigonometric identities?
  2. How do you derive tanx\tan x and secx\sec x using sine and cosine?
  3. Why is the identity sin2x+cos2x=1\sin^2 x + \cos^2 x = 1 important in trigonometry?
  4. How can we simplify expressions using trigonometric identities?
  5. What are some real-world applications of trigonometric identities?

Tip: Recognizing common trigonometric identities can help simplify complex expressions quickly.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities
Simplification of Trigonometric Expressions

Formulas

sec x = 1/cos x
tan x = sin x / cos x
sin^2 x + cos^2 x = 1

Theorems

Pythagorean Identity

Suitable Grade Level

Grades 10-12