Math Problem Statement

solve

Write an equivalent expression for each function that has no common factors in the numerator and denominator.

Solution

Let's solve each question step by step to identify the correct simplified expressions:


Problem 3

The given function is:

f(x)=3xx29f(x) = \frac{3x}{x^2 - 9}

  1. Factorize the denominator: x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3)

    The function becomes: f(x)=3x(x3)(x+3)f(x) = \frac{3x}{(x - 3)(x + 3)}

  2. Check for common factors: There are no common factors between 3x3x and (x3)(x+3)(x - 3)(x + 3), so the function cannot be simplified further.

    Answer: "Does not simplify."


Problem 4

The given function is:

g(x)=2x24x10x2+6xg(x) = \frac{2x^2 - 4x}{10x^2 + 6x}

  1. Factorize numerator and denominator:

    • Numerator: 2x24x=2x(x2)2x^2 - 4x = 2x(x - 2)
    • Denominator: 10x2+6x=2x(5x+3)10x^2 + 6x = 2x(5x + 3)

    The function becomes: g(x)=2x(x2)2x(5x+3)g(x) = \frac{2x(x - 2)}{2x(5x + 3)}

  2. Cancel the common factor 2x2x: g(x)=x25x+3g(x) = \frac{x - 2}{5x + 3}

    Answer: x25x+3\frac{x - 2}{5x + 3}


Problem 5

The given function is:

h(x)=4x2+10x7x2h(x) = \frac{4x^2 + 10x}{7x^2}

  1. Factorize numerator:

    • Numerator: 4x2+10x=2x(2x+5)4x^2 + 10x = 2x(2x + 5)

    The function becomes: h(x)=2x(2x+5)7x2h(x) = \frac{2x(2x + 5)}{7x^2}

  2. Cancel the common factor xx (assuming x0x \neq 0): h(x)=2(2x+5)7xh(x) = \frac{2(2x + 5)}{7x}

    Answer: 2(2x+5)7x\frac{2(2x + 5)}{7x}


Final Answers:

  1. Problem 3: Does not simplify.
  2. Problem 4: x25x+3\frac{x - 2}{5x + 3}
  3. Problem 5: 2(2x+5)7x\frac{2(2x + 5)}{7x}

Would you like a detailed breakdown for any specific part or additional explanation? Here are some related questions for practice:

  1. How do you identify common factors between numerator and denominator?
  2. What are the common errors in simplifying rational expressions?
  3. Can you simplify x24x2+4x+4\frac{x^2 - 4}{x^2 + 4x + 4}?
  4. How do you handle restrictions on xx when simplifying expressions?
  5. How do you approach a rational function that contains higher powers of xx?

Tip: Always factorize completely before canceling terms to ensure you simplify correctly!

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Functions
Factoring Polynomials
Simplifying Expressions

Formulas

Factoring difference of squares: a^2 - b^2 = (a - b)(a + b)
Factoring common terms from a polynomial
Simplifying rational expressions by canceling common factors

Theorems

Factoring Theorem
Cancellation Property of Rational Expressions

Suitable Grade Level

Grades 9-12