2 akar 3 didalam kurung 2 akar 40 ditambah akar 12

Mari kita pecahkan ekspresi ini:

\[
(2 \sqrt{3})(2 \sqrt{40}) + \sqrt{12}
\]

Langkah-langkah penyelesaiannya:

1. **Sederhanakan akar-akar**:
   - \( \sqrt{40} = \sqrt{4 \times 10} = 2 \sqrt{10} \)
   - \( \sqrt{12} = \sqrt{4 \times 3} = 2 \sqrt{3} \)

Jadi ekspresi menjadi:

\[
(2 \sqrt{3})(2 \times 2 \sqrt{10}) + 2 \sqrt{3}
\]

2. **Perkalian**:
   - \( (2 \sqrt{3})(4 \sqrt{10}) = 8 \sqrt{30} \)

Jadi, ekspresi sekarang:

\[
8 \sqrt{30} + 2 \sqrt{3}
\]

Tidak ada bentuk lebih lanjut yang bisa disederhanakan, jadi hasil akhirnya adalah:

\[
8 \sqrt{30} + 2 \sqrt

Solve and simplify the radical expression 2√3(2√40) + √12. This problem demonstrates key concepts such as multiplying and simplifying radicals. Step-by-step solution included. Suitable for Grades 9-10.

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