Math Problem Statement

2 akar 3 didalam kurung 2 akar 40 ditambah akar 12

Solution

Mari kita pecahkan ekspresi ini:

(23)(240)+12(2 \sqrt{3})(2 \sqrt{40}) + \sqrt{12}

Langkah-langkah penyelesaiannya:

  1. Sederhanakan akar-akar:
    • 40=4×10=210\sqrt{40} = \sqrt{4 \times 10} = 2 \sqrt{10}
    • 12=4×3=23\sqrt{12} = \sqrt{4 \times 3} = 2 \sqrt{3}

Jadi ekspresi menjadi:

(23)(2×210)+23(2 \sqrt{3})(2 \times 2 \sqrt{10}) + 2 \sqrt{3}

  1. Perkalian:
    • (23)(410)=830(2 \sqrt{3})(4 \sqrt{10}) = 8 \sqrt{30}

Jadi, ekspresi sekarang:

830+238 \sqrt{30} + 2 \sqrt{3}

Tidak ada bentuk lebih lanjut yang bisa disederhanakan, jadi hasil akhirnya adalah:

[ 8 \sqrt{30} + 2 \sqrt

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Math Problem Analysis

Mathematical Concepts

Radicals
Multiplication of Radicals
Simplification of Radicals

Formulas

√(a × b) = √a × √b
(a√b)(c√d) = ac√(bd)

Theorems

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Suitable Grade Level

Grades 9-10