Math Problem Statement

5 log 125

Solution

To solve 5log1255 \log 125, we can simplify it step by step.

Step 1: Use the multiplication rule of logarithms

The expression 5log1255 \log 125 can be rewritten as:

5log125=log12555 \log 125 = \log 125^5

Step 2: Simplify 1255125^5

First, recognize that 125=53125 = 5^3. So:

1255=(53)5=515125^5 = (5^3)^5 = 5^{15}

Step 3: Use the logarithmic property logab=bloga\log a^b = b \log a

Now, apply the logarithmic property:

log515=15log5\log 5^{15} = 15 \log 5

Step 4: Final calculation

Assuming the base of the logarithm is 10 (as implied when no base is given):

log50.69897\log 5 \approx 0.69897

Thus:

15log5=15×0.6989710.4845515 \log 5 = 15 \times 0.69897 \approx 10.48455

So, 5log12510.485 \log 125 \approx 10.48.

Would you like further details on any of the steps or a deeper explanation?


Here are five related questions:

  1. How do logarithmic properties help simplify expressions?
  2. What are the common logarithmic bases used in problems?
  3. Can you explain the change of base formula in logarithms?
  4. How does log(ab)\log (ab) relate to loga+logb\log a + \log b?
  5. What is the derivative of a logarithmic function?

Tip: When solving logarithmic problems, always check for simplifications using logarithmic properties like the product, quotient, and power rules.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponentiation

Formulas

log(a^b) = b * log(a)
a^b

Theorems

Logarithmic Power Rule
Logarithmic Multiplication Rule

Suitable Grade Level

Grades 10-12