To evaluate the expression \( \log_2 7 \times \log_2 16 \), let's break it down step by step.

### Step 1: Evaluate Each Logarithm
1. **Evaluate \( \log_2 7 \):**
   - \( \log_2 7 \) is the power to which 2 must be raised to get 7. This value is not an integer, so it remains in logarithmic form.

2. **Evaluate \( \log_2 16 \):**
   - \( \log_2 16 \) is the power to which 2 must be raised to get 16. Since \( 2^4 = 16 \), we have:
   \[
   \log_2 16 = 4
   \]

### Step 2: Multiply the Logarithms
Now, multiply the two logarithms:
\[
\log_2 7 \times \log_2 16 = \log_2 7 \times 4 = 4 \log_2 7
\]

This expression can be simplified to \( 4 \log_2 7 \), but since \( \log_2 7 \) is not a simple number, the expression remains in this form.

**Final Answer:**
\[
4 \log_2 7
\]

Would you like further details on logarithms, or do you have any other questions?

### Related Questions:
1. What are logarithms, and how are they used in different fields?
2. How do you simplify expressions involving multiple logarithms?
3. Can you change the base of a logarithm using a formula?
4. What is the relationship between exponential and logarithmic functions?
5. How do logarithms apply in real-world scenarios, like measuring sound intensity?

**Tip:** Remember that logarithms are the inverse operations of exponentiation, which means they "undo" the process of raising a number to a power.

Understand how to simplify the logarithmic expression log₂ 7 × log₂ 16 by evaluating each logarithm and applying the properties of logarithms. This problem is suitable for students in Grades 10-12 and covers key concepts in logarithms and algebra.

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