To evaluate the expression $\log_2 7 \times \log_2 16$, let's break it down step by step.

Step 1: Evaluate Each Logarithm

1. Evaluate $\log_2 7$:

   • $\log_2 7$ is the power to which 2 must be raised to get 7. This value is not an integer, so it remains in logarithmic form.

2. Evaluate $\log_2 16$:

   • $\log_2 16$ is the power to which 2 must be raised to get 16. Since $2^4 = 16$, we have: $\log_2 16 = 4$

Step 2: Multiply the Logarithms

Now, multiply the two logarithms: $\log_2 7 \times \log_2 16 = \log_2 7 \times 4 = 4 \log_2 7$

This expression can be simplified to $4 \log_2 7$, but since $\log_2 7$ is not a simple number, the expression remains in this form.

Final Answer: $4 \log_2 7$

Would you like further details on logarithms, or do you have any other questions?

Related Questions:

1. What are logarithms, and how are they used in different fields?
2. How do you simplify expressions involving multiple logarithms?
3. Can you change the base of a logarithm using a formula?
4. What is the relationship between exponential and logarithmic functions?
5. How do logarithms apply in real-world scenarios, like measuring sound intensity?

Tip: Remember that logarithms are the inverse operations of exponentiation, which means they "undo" the process of raising a number to a power.