Math Problem Statement

0.5 log 0.5 + 0.5 log 0.5

Solution

The expression given is:

0.5log0.5+0.5log0.50.5 \log 0.5 + 0.5 \log 0.5

First, we can simplify the terms.

0.5log0.5+0.5log0.5=2×(0.5log0.5)0.5 \log 0.5 + 0.5 \log 0.5 = 2 \times (0.5 \log 0.5)

Now, simplifying further:

2×(0.5log0.5)=log0.52 \times (0.5 \log 0.5) = \log 0.5

We know that:

log0.5=log(12)=log2\log 0.5 = \log \left( \frac{1}{2} \right) = -\log 2

Thus, the simplified result is:

log0.5=log2\log 0.5 = -\log 2

Therefore, the final answer is:

log2-\log 2

Would you like more details or have any questions?


Here are 5 related questions to expand on this topic:

  1. What are the properties of logarithms and how do they help simplify expressions?
  2. How would this expression change if it involved a natural logarithm instead?
  3. What is the value of log2\log 2 and how is it used in different contexts?
  4. How can logarithmic expressions like these be applied in solving exponential equations?
  5. What is the relationship between log\log and ln\ln, and how are they used differently?

Tip: Always remember that log1x=logx\log \frac{1}{x} = -\log x, a useful property when dealing with fractions in logarithmic expressions.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Properties of Logarithms

Formulas

0.5 log a + 0.5 log a = log a
log(1/x) = -log(x)

Theorems

Logarithmic Identity
Properties of Logarithms

Suitable Grade Level

Grades 9-11