Math Problem Statement

berikan penyelesaian

berikan penyelesaian

Solution

The equation shown in the image is:

15!13!×3!\frac{15!}{13! \times 3!}

To simplify this expression, let's break it down step by step:

  1. Factorial Definition:

    • 15!=15×14×13×12××115! = 15 \times 14 \times 13 \times 12 \times \dots \times 1
    • 13!=13×12×11××113! = 13 \times 12 \times 11 \times \dots \times 1
    • 3!=3×2×1=63! = 3 \times 2 \times 1 = 6
  2. Simplify Factorials:

    • We can cancel out the common 13!13! in both the numerator and denominator:

    15!13!×3!=15×14×13!13!×3!\frac{15!}{13! \times 3!} = \frac{15 \times 14 \times 13!}{13! \times 3!}

    The 13!13! terms cancel out, leaving us with:

    15×143!=15×146\frac{15 \times 14}{3!} = \frac{15 \times 14}{6}

  3. Simplify Further:

    • Multiply 15 and 14: 15×14=21015 \times 14 = 210
    • Divide by 6: 2106=35\frac{210}{6} = 35

So, the final result is:

35\boxed{35}

Would you like further details on factorials or another related topic?

Here are some related questions you might find interesting:

  1. How do we define a factorial in mathematics?
  2. What are some properties of factorials that can simplify complex calculations?
  3. How do combinations and permutations relate to factorials?
  4. What is the difference between n!n! and (n1)!(n-1)!?
  5. Can factorials be computed efficiently for very large numbers?

Tip: Factorial operations can be simplified by canceling out common terms in the numerator and denominator to avoid calculating large numbers.

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Math Problem Analysis

Mathematical Concepts

Factorials
Simplification
Combinatorics

Formulas

n! = n × (n-1) × (n-2) × ... × 1
n! / (r!(n-r)!) = Combination Formula

Theorems

Factorial Properties

Suitable Grade Level

Grades 9-12