Math Problem Statement

−1/2(8×14÷2+5−(6−∣−6∣) −7)

Solution

Let's solve the expression step by step:

12(8×14÷2+5(66)7)-\frac{1}{2} \left( 8 \times 14 \div 2 + 5 - (6 - | -6 |) - 7 \right)

Step 1: Simplify inside the absolute value

The absolute value of 6-6 is: 6=6| -6 | = 6 So the expression becomes: 12(8×14÷2+5(66)7)-\frac{1}{2} \left( 8 \times 14 \div 2 + 5 - (6 - 6) - 7 \right)

Step 2: Simplify inside the parentheses

66=06 - 6 = 0, so: 12(8×14÷2+507)=12(8×14÷2+57)-\frac{1}{2} \left( 8 \times 14 \div 2 + 5 - 0 - 7 \right) = -\frac{1}{2} \left( 8 \times 14 \div 2 + 5 - 7 \right)

Step 3: Perform multiplication and division

8×14=112,112÷2=568 \times 14 = 112, \quad 112 \div 2 = 56 So the expression is now: 12(56+57)-\frac{1}{2} \left( 56 + 5 - 7 \right)

Step 4: Simplify inside the parentheses

56+57=5456 + 5 - 7 = 54 So the expression becomes: 12×54-\frac{1}{2} \times 54

Step 5: Perform the multiplication

12×54=27-\frac{1}{2} \times 54 = -27

Thus, the value of the expression is:

27\boxed{-27}

Would you like more details or have any questions about this solution?

Here are 5 related questions:

  1. What is the value of 13(9×64+2)\frac{1}{3}(9 \times 6 - 4 + | -2 |)?
  2. How do you evaluate expressions with absolute values?
  3. How does the distributive property work in expressions like 12(a+b)-\frac{1}{2}(a + b)?
  4. What are the rules for performing operations inside parentheses first (PEMDAS)?
  5. How does multiplying by a negative fraction affect the result?

Tip: Always solve expressions inside absolute values first before applying any other operations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value
Order of Operations
Multiplication and Division
Fraction Operations

Formulas

Order of Operations (PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right))
Absolute Value |x| = x if x ≥ 0; |x| = -x if x < 0

Theorems

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Suitable Grade Level

Grades 7-9