Math Problem Statement

-3e^(-x/3)(x^2+1)-18e^(-x/3)*x-9e^(-x/3)

Solution

The given expression can be simplified step by step by factoring common terms where possible. Let’s analyze and simplify:

Expression:

3ex3(x2+1)18ex3x9ex3-3e^{-\frac{x}{3}}(x^2 + 1) - 18e^{-\frac{x}{3}}x - 9e^{-\frac{x}{3}}

Step 1: Identify the common factor

The common factor across all terms is: 3ex3-3e^{-\frac{x}{3}}

Step 2: Factor out 3ex3-3e^{-\frac{x}{3}}

Factoring it out from all terms, we get: 3ex3[(x2+1)+6x+3]-3e^{-\frac{x}{3}} \big[(x^2 + 1) + 6x + 3 \big]

Step 3: Simplify inside the brackets

Combine like terms: x2+6x+1+3=x2+6x+4x^2 + 6x + 1 + 3 = x^2 + 6x + 4

Thus, the factored expression becomes: 3ex3(x2+6x+4)-3e^{-\frac{x}{3}}(x^2 + 6x + 4)

Final Simplified Expression:

3ex3(x2+6x+4)-3e^{-\frac{x}{3}}(x^2 + 6x + 4)

This is the simplified version of the given expression.


Would you like further details, or do you have any questions about this process? 😊

Here are 5 related questions to explore:

  1. How can you expand the factored expression back to verify the result?
  2. What are the roots of the quadratic equation x2+6x+4=0x^2 + 6x + 4 = 0?
  3. How does the exponential term ex3e^{-\frac{x}{3}} affect the behavior of the function as xx \to \infty?
  4. Can you determine the critical points of the function?
  5. What is the derivative of the simplified expression?

Tip: Always look for common factors when simplifying algebraic expressions—it often makes the work more manageable!

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Math Problem Analysis

Mathematical Concepts

Algebra
Exponential Functions
Factoring
Quadratic Expressions

Formulas

Factoring out common terms
Quadratic form (ax^2 + bx + c)

Theorems

Factorization Theorem

Suitable Grade Level

Grades 10-12