Math Problem Statement

Find f(a + h) - f(a) h and simplify where, (i) f(x) = 6x - 9

Solution

We are tasked with finding the expression f(a+h)f(a)h\frac{f(a+h) - f(a)}{h} and simplifying it for the given function f(x)=6x9f(x) = 6x - 9.

Step 1: Determine f(a+h)f(a + h)

Since f(x)=6x9f(x) = 6x - 9, replace xx with a+ha + h to get: f(a+h)=6(a+h)9=6a+6h9f(a + h) = 6(a + h) - 9 = 6a + 6h - 9

Step 2: Determine f(a)f(a)

Now, find f(a)f(a) by replacing xx with aa in the function f(x)f(x): f(a)=6a9f(a) = 6a - 9

Step 3: Calculate f(a+h)f(a)f(a + h) - f(a)

Now subtract f(a)f(a) from f(a+h)f(a + h): f(a+h)f(a)=(6a+6h9)(6a9)f(a + h) - f(a) = (6a + 6h - 9) - (6a - 9) Simplifying the expression: f(a+h)f(a)=6a+6h96a+9=6hf(a + h) - f(a) = 6a + 6h - 9 - 6a + 9 = 6h

Step 4: Divide by hh

Now, divide the result by hh: f(a+h)f(a)h=6hh=6\frac{f(a + h) - f(a)}{h} = \frac{6h}{h} = 6

Final Answer:

f(a+h)f(a)h=6\frac{f(a+h) - f(a)}{h} = 6

Would you like further details or have any questions?

Here are 5 related questions to expand on this:

  1. How would the result change if f(x)f(x) were a quadratic function?
  2. What is the significance of this expression in calculus?
  3. Can you apply the same steps if f(x)=3x22x+1f(x) = 3x^2 - 2x + 1?
  4. How would you interpret this result geometrically?
  5. What happens to the expression if hh approaches 0?

Tip: The expression f(a+h)f(a)h\frac{f(a+h) - f(a)}{h} is the difference quotient, a fundamental concept in finding the derivative of a function.

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Math Problem Analysis

Mathematical Concepts

Algebra
Difference Quotient
Linear Functions

Formulas

f(a + h) = 6(a + h) - 9
f(a) = 6a - 9
\(\frac{f(a + h) - f(a)}{h}\)

Theorems

Difference Quotient

Suitable Grade Level

Grades 9-12