Math Problem Statement

simplify the expression to a + bi form: (-3+I)-(1+10i)

Solution

To simplify the expression (3+i)(1+10i)(-3 + i) - (1 + 10i) into the form a+bia + bi:

  1. Distribute the negative sign: (3+i)110i=3+i110i(-3 + i) - 1 - 10i = -3 + i - 1 - 10i

  2. Combine the real parts (3(-3 and 1)-1) and the imaginary parts (i(i and 10i)-10i): (31)+(i10i)=49i(-3 - 1) + (i - 10i) = -4 - 9i

Thus, the expression simplifies to: 49i-4 - 9i

This is in the form a+bia + bi, where a=4a = -4 and b=9b = -9.

Would you like further details or have any questions?

Here are five related questions to explore this concept further:

  1. How do you add or subtract two complex numbers?
  2. What happens if you multiply two complex numbers instead of adding them?
  3. How do you calculate the magnitude of a complex number?
  4. What is the geometric interpretation of complex numbers in the complex plane?
  5. How do you convert a complex number from rectangular form to polar form?

Tip: Always group the real and imaginary parts separately when simplifying expressions with complex numbers.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Addition and Subtraction of Complex Numbers

Formulas

(a + bi) ± (c + di) = (a ± c) + (b ± d)i

Theorems

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Suitable Grade Level

Grades 10-12