(−10+9i)−4(1−2i) Solve ﻿﻿and write the answer in standard form.

Let's solve \((−10 + 9i) − 4(1 − 2i)\) and express the answer in standard form, which is \(a + bi\).

1. Distribute the \(-4\) to both terms inside the parentheses:
\[
4(1 − 2i) = 4 \cdot 1 + 4 \cdot (−2i) = 4 − 8i
\]

2. Now substitute this into the original expression:
\[
(−10 + 9i) − (4 − 8i)
\]

3. Distribute the negative sign:
\[
−10 + 9i − 4 + 8i
\]

4. Combine the real parts and the imaginary parts:
\[
(−10 − 4) + (9i + 8i) = −14 + 17i
\]

So the solution in standard form is:
\[
\boxed{−14 + 17i}
\]

Would you like further clarification on any part of the solution?

Here are 5 related questions you might find helpful:
1. How do you multiply two complex numbers?
2. What is the conjugate of a complex number, and how do you use it?
3. How do you divide complex numbers?
4. What is the geometric interpretation of a complex number?
5. How do you find the modulus of a complex number?

**Tip:** When solving with complex numbers, always combine real and imaginary parts separately for clarity.

Solve (−10 + 9i) − 4(1 − 2i) and write the answer in standard form.

Solve the complex number expression (−10 + 9i) − 4(1 − 2i) step-by-step. This problem demonstrates how to handle complex numbers, using basic algebraic operations and expressing the result in standard form. Ideal for Grades 10-12.

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