Math Problem Statement

Multiple problems on simplifying algebraic expressions and exponents in Swedish from the given image.

Solution

Let's go through each of the problems in the image and solve them step by step.

Problem 1212

Problem: Antonia simplifies the expression (6xy)2(6xy)^2 to 6x2y26x^2y^2. Explain what she did wrong.

Solution: Antonia's mistake is that she didn't square the constant 6. The correct simplification should be: (6xy)2=62x2y2=36x2y2.(6xy)^2 = 6^2 \cdot x^2 \cdot y^2 = 36x^2y^2. So, the correct answer is 36x2y236x^2y^2.

Problem 1213

Simplify as much as possible:

(a) 2x4x3\frac{2x^4}{x^3}

Simplify by subtracting the exponents: 2x4x3=2x43=2x.\frac{2x^4}{x^3} = 2x^{4-3} = 2x.

(b) x2x11x3\frac{x^2 \cdot x^{11}}{x^3}

Combine the exponents in the numerator and then subtract the exponent in the denominator: x2x11x3=x2+11x3=x133=x10.\frac{x^2 \cdot x^{11}}{x^3} = \frac{x^{2+11}}{x^3} = x^{13-3} = x^{10}.

(c) a2a11a3a3a2\frac{a^2 \cdot a^{11}}{a^3 \cdot a^3 \cdot a^2}

Combine the exponents in the numerator and denominator: a2a11a3a3a2=a2+11a3+3+2=a13a8=a138=a5.\frac{a^2 \cdot a^{11}}{a^3 \cdot a^3 \cdot a^2} = \frac{a^{2+11}}{a^{3+3+2}} = \frac{a^{13}}{a^{8}} = a^{13-8} = a^5.

(d) (5x)2x\frac{(5x)^2}{x}

Simplify by expanding and then subtract the exponents: (5x)2x=25x2x=25x21=25x.\frac{(5x)^2}{x} = \frac{25x^2}{x} = 25x^{2-1} = 25x.

Problem 1214

Write as a power with the given base:

(a) 34273^4 \cdot 27 (base 3)

Since 27=3327 = 3^3, the expression becomes: 3433=34+3=37.3^4 \cdot 3^3 = 3^{4+3} = 3^7.

(b) (52)7125(5^2)^7 \cdot 125 (base 5)

Since 125=53125 = 5^3, the expression becomes: (52)753=51453=514+3=517.(5^2)^7 \cdot 5^3 = 5^{14} \cdot 5^3 = 5^{14+3} = 5^{17}.

(c) 8132\frac{81}{3^2} (base 3)

Since 81=3481 = 3^4, the expression becomes: 3432=342=32.\frac{3^4}{3^2} = 3^{4-2} = 3^2.

(d) 232422 \cdot 32 \cdot 4^2 (base 2)

Since 32=2532 = 2^5 and 4=224 = 2^2, the expression becomes: 225(22)2=212524=21+5+4=210.2 \cdot 2^5 \cdot (2^2)^2 = 2^1 \cdot 2^5 \cdot 2^4 = 2^{1+5+4} = 2^{10}.

Problem 1215

Write the expressions as a single power of a product:

(a) 23x32^3 \cdot x^3

Combine the powers: 23x3=(2x)3.2^3 \cdot x^3 = (2x)^3.

(b) 32y23^2 \cdot y^2

Combine the powers: 32y2=(3y)2.3^2 \cdot y^2 = (3y)^2.

(c) a3b3a^3 \cdot b^3

Combine the powers: a3b3=(ab)3.a^3 \cdot b^3 = (ab)^3.

Would you like more details on any of these solutions, or do you have any questions?

Here are some related questions to further your understanding:

  1. How can you verify the simplification of exponents when dividing powers with the same base?
  2. What is the rule for raising a power to another power in exponentiation?
  3. How do you simplify expressions involving products and quotients of exponents?
  4. Can you convert expressions to a single power when the bases are different?
  5. How do you approach simplifying more complex expressions involving multiple exponent rules?

Tip: When simplifying expressions with exponents, remember to apply the rules systematically: combine like terms, add or subtract exponents where appropriate, and be careful with the bases!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponents
Simplifying algebraic expressions
Powers of products
Exponent rules for multiplication and division

Formulas

a^m * a^n = a^(m+n)
(a^m)^n = a^(m*n)
a^m / a^n = a^(m-n)

Theorems

Laws of Exponents

Suitable Grade Level

Grades 9-11