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I can help you solve the problems from the worksheet you provided. Let's start with the first section and work through it step by step.

### 1. Evaluate the below expressions:

#### Problem 1: 
\[
(3^3 \cdot 2^2)^2
\]

- First, simplify inside the parentheses:
  - \( 3^3 = 27 \)
  - \( 2^2 = 4 \)
  - So, \( 27 \cdot 4 = 108 \)

- Now raise \( 108 \) to the power of 2:
  \[
  108^2 = 11,664
  \]

So, the solution is \( 11,664 \).

#### Problem 2: 
\[
\left( \frac{-2}{5} \right)^3 \cdot \left( \frac{2}{3} \right)^2
\]

- First, calculate the powers separately:
  - \( \left( \frac{-2}{5} \right)^3 = \frac{(-2)^3}{5^3} = \frac{-8}{125} \)
  - \( \left( \frac{2}{3} \right)^2 = \frac{2^2}{3^2} = \frac{4}{9} \)

- Multiply the two fractions:
  \[
  \frac{-8}{125} \cdot \frac{4}{9} = \frac{-8 \cdot 4}{125 \cdot 9} = \frac{-32}{1125}
  \]

So, the solution is \( \frac{-32}{1125} \).

#### Problem 3: 
\[
(-3)^0 \cdot (-4)^{-2}
\]

- \( (-3)^0 = 1 \) (Any number to the power of 0 is 1)
- \( (-4)^{-2} = \frac{1}{(-4)^2} = \frac{1}{16} \)

- Multiply:
  \[
  1 \cdot \frac{1}{16} = \frac{1}{16}
  \]

So, the solution is \( \frac{1}{16} \).

#### Problem 4:
Given

Solve exponent problems from the worksheet. This includes evaluating expressions, simplifying exponentials, converting radicals to exponential form, and solving complex fractions with exponents.

This page provides step-by-step solutions to exponent problems involving simplification, evaluation, and radical conversion. It covers exponent laws, including multiplication, division, and negative exponents, along with fractional exponent rules. Suitable for students in Grades 8-10.

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