Let's simplify the expression:

\[
\frac{(5x^2)(3x^{-2})}{1}
\]

Step 1: Multiply the constants:

\[
5 \times 3 = 15
\]

Step 2: Apply the law of exponents for the \(x\) terms:

\[
x^2 \times x^{-2} = x^{(2 + (-2))} = x^0
\]

Since \(x^0 = 1\), the expression becomes:

\[
15 \times 1 = 15
\]

Thus, the simplified expression is:

\[
\boxed{15}
\]

Would you like more details or have any questions?

Here are 5 related questions for practice:
1. Simplify \((2x^3)(4x^{-1})\).
2. What is the result of \((7x^5)(2x^{-3})\)?
3. Simplify \((8x^4)(3x^{-4})\).
4. How do you simplify \((6x^3)(5x^{-3})\)?
5. What is the simplified form of \((9x^2)(2x^0)\)?

**Tip**: When multiplying powers of the same base, add their exponents.

Learn how to simplify the algebraic expression (5x^2)(3x^-2) using the laws of exponents. This solution involves key concepts in algebra and is suitable for students in Grades 8-10.

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