The expression shown in the image is:

$(5a^{-3}b^{-4})(2a^{2}b^{5}) = 10a^{-1}b$

Step-by-step Explanation:

1. Multiply the constants:
   The constants are $5$ and $2$. When multiplying these, we get: $5 \times 2 = 10$

2. Add the exponents of $a$:
   Using the law of exponents, $a^m \times a^n = a^{m+n}$, we add the exponents of $a$ in the two terms: $a^{-3} \times a^2 = a^{-3+2} = a^{-1}$

3. Add the exponents of $b$:
   Similarly, we add the exponents of $b$: $b^{-4} \times b^5 = b^{-4+5} = b^1$

Thus, the simplified form of the expression is: $10a^{-1}b$

This matches the given result.

Would you like further details or have any questions?

Here are some related questions for practice:

1. How do you simplify $(3a^5b^2)(4a^{-3}b^{-6})$?
2. What is the result of $(6x^{-4}y^3)(5x^2y^{-2})$?
3. Can you simplify $(7c^3d^{-1})(2c^{-5}d^4)$?
4. How do you apply the power of a product rule to expressions like $(2ab^3)^2$?
5. What happens when you multiply two terms where one variable has a zero exponent?

Tip: Always remember to add exponents when multiplying terms with the same base.