To solve the expression \( 2x + 3x \times 44 \), we need to follow the order of operations (PEMDAS/BODMAS).

1. **Multiplication first**: Multiply \( 3x \) by 44.
   \[
   3x \times 44 = 132x
   \]

2. **Addition**: Add \( 2x \) to \( 132x \).
   \[
   2x + 132x = 134x
   \]

So, the simplified expression is \( 134x \).

Would you like further details or have any questions?

Here are some related questions:

1. How would the expression change if it was \( 2x + 3(x \times 44) \)?
2. What is the value of \( x \) if \( 134x = 268 \)?
3. How would you simplify \( 2x + 3x \times 44 + 5x \)?
4. What happens if we substitute \( x = 1 \) into the expression?
5. How can we solve for \( x \) if the expression equals a specific number?

**Tip**: Always remember to perform multiplication and division before addition and subtraction when simplifying expressions!

Learn how to simplify the algebraic expression 2x + 3x × 44 using the order of operations (PEMDAS/BODMAS). This step-by-step guide demonstrates how to first handle multiplication and then addition to arrive at the simplified result of 134x. Suitable for students in Grades 6-8.

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