Math Problem Statement

Simplify: cosθ[cosθsinθ−sinθcosθ]+sinθ[sinθ−cosθcosθsinθ]

Solution

Let's simplify the given expression step by step:

The expression is:

[ \cos\theta \left[\cos\theta \sin\theta - \sin\theta \cos\theta \right] + \sin\theta \left[\sin\theta - \cos\theta \cos\theta \sin\theta \right] ]

Step 1: Simplify each bracket

  1. First bracket: cosθsinθsinθcosθ\cos\theta \sin\theta - \sin\theta \cos\theta Notice that the two terms are the same but with opposite signs, so: cosθsinθsinθcosθ=0\cos\theta \sin\theta - \sin\theta \cos\theta = 0

  2. Second bracket: sinθcosθcosθsinθ\sin\theta - \cos\theta \cos\theta \sin\theta This can be simplified by factoring sinθ\sin\theta: sinθ(1cos2θ)\sin\theta (1 - \cos^2\theta) Using the Pythagorean identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1, we can replace 1cos2θ1 - \cos^2\theta with sin2θ\sin^2\theta: sinθsin2θ=sin3θ\sin\theta \sin^2\theta = \sin^3\theta

Step 2: Substitute back into the original expression

The expression now becomes: cosθ0+sinθsin3θ\cos\theta \cdot 0 + \sin\theta \cdot \sin^3\theta Which simplifies to: 0+sin4θ0 + \sin^4\theta

Final Answer

The simplified expression is:

sin4θ\sin^4\theta

Would you like more details or have any questions about this? Here are five related questions you might find interesting:

  1. How do you simplify trigonometric expressions involving multiple identities?
  2. What is the Pythagorean identity and how is it used in trigonometry?
  3. Can you derive the double angle formulas using trigonometric identities?
  4. How do you prove trigonometric identities step by step?
  5. What are the applications of trigonometric identities in calculus?

Tip: When simplifying trigonometric expressions, always look for opportunities to apply fundamental identities like the Pythagorean identity.