Simplify.

StartRoot StartFraction 1 Over 36 EndFraction EndRoot136

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Part 1

Select the correct choice below​ and, if​ necessary, fill in the answer box within your choice.

A.StartRoot StartFraction 1 Over 36 EndFraction EndRoot equals enter your response here

StartRoot StartFraction 1 Over 36 EndFraction EndRoot equals136=enter your response here

B.

 The root is not a real number.

Let's simplify the expression:

\[
\sqrt{\frac{1}{36}}
\]

1. First, simplify \(\sqrt{\frac{1}{36}}\):
   \[
   \sqrt{\frac{1}{36}} = \frac{\sqrt{1}}{\sqrt{36}}
   \]

2. Calculate the square roots:
   \[
   \sqrt{1} = 1 \quad \text{and} \quad \sqrt{36} = 6
   \]

3. Substitute these values:
   \[
   \sqrt{\frac{1}{36}} = \frac{1}{6}
   \]

Therefore, the answer is:

\[
\sqrt{\frac{1}{36}} = \frac{1}{6}
\]

The correct answer is **A**:  
\[
\sqrt{\frac{1}{36}} = \frac{1}{6}
\]

Would you like further details or have any questions?

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### Related Questions:
1. How would you simplify \(\sqrt{\frac{4}{49}}\)?
2. What is the simplified form of \(\sqrt{\frac{9}{16}}\)?
3. How do you determine if the square root of a fraction is a real number?
4. How would you express \(\sqrt{\frac{25}{81}}\) as a simplified fraction?
5. What does it mean for a number to have a "real" square root?

### Tip:
When simplifying square roots of fractions, remember that \(\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\) if both \(a\) and \(b\) have real square roots.

Simplify. \(\sqrt{\frac{1}{36}}\)

Select the correct choice below and, if necessary, fill in the answer box within your choice.

A. \(\sqrt{\frac{1}{36}}\) = enter your response here

B. The root is not a real number.

Learn how to simplify \(\sqrt{\frac{1}{36}}\) using square root properties. This problem covers fundamental concepts in algebra, including square roots and fractions, and is suitable for students in Grades 6-8.

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