The problem shown in the image asks to simplify the square root of 63, or $\sqrt{63}$.

To simplify this:

1. First, find the prime factors of 63: $63 = 3^2 \times 7$

2. Now, rewrite the square root: $\sqrt{63} = \sqrt{3^2 \times 7} = \sqrt{3^2} \times \sqrt{7} = 3\sqrt{7}$

Thus, the simplified form of $\sqrt{63}$ is $3\sqrt{7}$.

Would you like more details on this? Here are some related questions:

1. How do you simplify square roots of non-perfect squares?
2. What are prime factorization methods for large numbers?
3. How do square roots behave under multiplication?
4. How can you approximate non-perfect square roots like $\sqrt{7}$?
5. What are common mistakes when simplifying radicals?

Tip: When simplifying square roots, always look for perfect square factors.