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The problem is asking to simplify the square root of 68, \(\sqrt{68}\), and select the correct answer from the given options.

### Step-by-step solution:
1. **Prime factorization of 68:**
   - 68 can be written as \(68 = 2^2 \times 17\).
   
2. **Simplifying the square root:**
   - \(\sqrt{68} = \sqrt{2^2 \times 17} = \sqrt{2^2} \times \sqrt{17} = 2\sqrt{17}\).

Thus, the simplest form of \(\sqrt{68}\) is \(2\sqrt{17}\), which matches option **D**.

Would you like more details or have any questions?

### Related questions:
1. What is the simplified form of \(\sqrt{72}\)?
2. How would you simplify \(\sqrt{32}\)?
3. What are the steps to simplify \(\sqrt{50}\)?
4. Can you explain how to simplify \(\sqrt{45}\)?
5. What is the prime factorization method for simplifying radicals?

### Tip:
Always look for perfect square factors when simplifying square roots.

What is \( \sqrt{68} \) in simplest form?

Learn how to simplify the square root of 68 using prime factorization. This problem involves key concepts in algebra, particularly the simplification of radical expressions. Suitable for students in Grades 8-10.

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