To simplify $\sqrt{320}$, follow these steps:

1. Factorize 320: $320 = 2^6 \times 5$

2. Use the square root property: $\sqrt{320} = \sqrt{2^6 \times 5} = \sqrt{2^6} \times \sqrt{5}$

3. Simplify $\sqrt{2^6}$: Since $2^6 = (2^3)^2$, we have: $\sqrt{2^6} = 2^3 = 8$

4. Combine the results: $\sqrt{320} = 8 \times \sqrt{5}$

Final Answer:

$\sqrt{320} = 8\sqrt{5}$

Would you like more explanation or examples related to this topic?

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Related Questions:

1. How do you simplify the square root of other composite numbers?
2. What is the process to find the square root of a number that isn't a perfect square?
3. How do you rationalize square root denominators?
4. How is prime factorization used in simplifying radicals?
5. What are the rules for multiplying and dividing square roots?

Tip: Always look for the largest perfect square factor of a number when simplifying square roots.