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The problem asks us to simplify the expression: 

\[
\sqrt{15} \cdot \sqrt{15}.
\]

### Solution:
1. Recall the property of square roots:
   \[
   \sqrt{a} \cdot \sqrt{a} = a.
   \]
2. Applying this property:
   \[
   \sqrt{15} \cdot \sqrt{15} = 15.
   \]

Thus, the simplified result is **15**. 

The correct answer is **D**.

---

Would you like a detailed explanation of square root properties or more examples?  

### Related Questions:
1. What happens when you multiply square roots of different numbers, e.g., \(\sqrt{5} \cdot \sqrt{3}\)?
2. How would you simplify \(\sqrt{16} \cdot \sqrt{16}\)?
3. Why does \(\sqrt{a} \cdot \sqrt{a} = a\)?
4. How would this change if the square roots involved fractions, e.g., \(\sqrt{\frac{1}{4}} \cdot \sqrt{\frac{1}{4}}\)?
5. How do you simplify a square root expression like \(\sqrt{30}\)?

### Tip:
Always check if a square root multiplication forms a perfect square — this simplifies directly to the base number!

Simplify \( \sqrt{15} \cdot \sqrt{15} \).

Learn how to simplify the expression \( \sqrt{15} \cdot \sqrt{15} \) using the property of square roots. This step-by-step guide explains the mathematical concepts, including the formula \( \sqrt{a} \cdot \sqrt{a} = a \), suitable for students in Grades 6-8.

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