Math Problem Statement

Simplify \( \sqrt{15} \cdot \sqrt{15} \).

Solution

The problem asks us to simplify the expression:

1515.\sqrt{15} \cdot \sqrt{15}.

Solution:

  1. Recall the property of square roots: aa=a.\sqrt{a} \cdot \sqrt{a} = a.
  2. Applying this property: 1515=15.\sqrt{15} \cdot \sqrt{15} = 15.

Thus, the simplified result is 15.

The correct answer is D.


Would you like a detailed explanation of square root properties or more examples?

Related Questions:

  1. What happens when you multiply square roots of different numbers, e.g., 53\sqrt{5} \cdot \sqrt{3}?
  2. How would you simplify 1616\sqrt{16} \cdot \sqrt{16}?
  3. Why does aa=a\sqrt{a} \cdot \sqrt{a} = a?
  4. How would this change if the square roots involved fractions, e.g., 1414\sqrt{\frac{1}{4}} \cdot \sqrt{\frac{1}{4}}?
  5. How do you simplify a square root expression like 30\sqrt{30}?

Tip:

Always check if a square root multiplication forms a perfect square — this simplifies directly to the base number!

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Math Problem Analysis

Mathematical Concepts

Properties of square roots
Simplifying expressions

Formulas

\( \sqrt{a} \cdot \sqrt{a} = a \)

Theorems

Square root multiplication property

Suitable Grade Level

Grades 6-8