Math Problem Statement

\sqrt(2\sqrt(4^(x)))

Solution

Let's simplify the given expression step by step:

24x\sqrt{2\sqrt{4^x}}

  1. Start with the inner expression 4x\sqrt{4^x}: 4x=(4x)1/2=4x/2\sqrt{4^x} = (4^x)^{1/2} = 4^{x/2}

  2. Substitute this back into the original expression: 24x=24x/2\sqrt{2\sqrt{4^x}} = \sqrt{2 \cdot 4^{x/2}}

  3. Write 4x/24^{x/2} as (22)x/2(2^2)^{x/2}, which simplifies using exponent rules: (22)x/2=22(x/2)=2x(2^2)^{x/2} = 2^{2 \cdot (x/2)} = 2^x

    So, 24x/2=22x\sqrt{2 \cdot 4^{x/2}} = \sqrt{2 \cdot 2^x}.

  4. Combine 22 and 2x2^x using the property of exponents: 22x=21+x2 \cdot 2^x = 2^{1 + x}

  5. Now the expression becomes: 21+x\sqrt{2^{1 + x}}

  6. Apply the square root to the exponent: 21+x=2(1+x)/2\sqrt{2^{1 + x}} = 2^{(1 + x)/2}

Thus, the simplified expression is:

2(1+x)/22^{(1 + x)/2}


Do you have any questions about this solution or want to explore related concepts? Here are five questions you might find helpful to expand your understanding:

  1. How do exponentiation and roots interact when simplifying expressions?
  2. What are some other examples of simplifying nested radicals?
  3. How can we verify the correctness of such simplifications using specific values of xx?
  4. What are the properties of exponential expressions that make them useful in solving equations?
  5. How does the base of the exponent affect the simplification process?

Tip: Always break down nested expressions step by step, starting from the innermost part, to avoid errors in simplification.

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Math Problem Analysis

Mathematical Concepts

Radicals
Exponents
Simplification

Formulas

√(a√b) = √a × b^(1/2)
(a^m)^n = a^(m*n)
a^m × a^n = a^(m+n)

Theorems

Laws of Exponents
Properties of Square Roots

Suitable Grade Level

Grades 9-12