Math Problem Statement

Simplify general quadratic polynomial sequences

Solution

General quadratic polynomial sequences can be represented by the expression:

an=an2+bn+ca_n = an^2 + bn + c

where:

  • aa, bb, and cc are constants, and
  • nn is the term number in the sequence.

To simplify such sequences, follow these steps:

  1. Identify the Sequence Formula: Given a sequence, determine the general formula by recognizing it as a quadratic sequence. The sequence is typically provided as values, such as a1,a2,a3,a_1, a_2, a_3, \dots, where ana_n represents the nnth term.

  2. Calculate the First Differences: Compute the first differences by subtracting each consecutive term in the sequence: Δ1=an+1an\Delta_1 = a_{n+1} - a_n For quadratic sequences, the first differences will themselves form an arithmetic sequence.

  3. Calculate the Second Differences: Compute the differences between consecutive first differences: Δ2=Δ1,n+1Δ1,n\Delta_2 = \Delta_{1,n+1} - \Delta_{1,n} For quadratic sequences, the second differences will be constant.

  4. Determine the Coefficients aa, bb, and cc:

    • The constant second difference is equal to 2a2a.
    • Use the system of equations derived from substituting small values of nn (like 1, 2, 3) into the general formula an=an2+bn+ca_n = an^2 + bn + c to solve for aa, bb, and cc.
  5. Write the Simplified Sequence Formula: Substitute the calculated coefficients back into the general formula to obtain the simplified sequence formula.

Example

Given a sequence: 2,6,12,20,2, 6, 12, 20, \dots

  1. First differences: 62=46 - 2 = 4, 126=612 - 6 = 6, 2012=820 - 12 = 8
  2. Second differences: 64=26 - 4 = 2, 86=28 - 6 = 2 (constant)

Since the second difference is constant and equal to 2, we have 2a=2a=12a = 2 \Rightarrow a = 1.

Using the first term a1=2a_1 = 2: an=n2+bn+ca_n = n^2 + bn + c Substitute n=1n = 1: 12+b(1)+c=21+b+c=21^2 + b(1) + c = 2 \Rightarrow 1 + b + c = 2 Substitute n=2n = 2 to find bb and cc.

Would you like to see further details of this process?

Relative Questions:

  1. How do you determine the first differences in a sequence?
  2. What indicates that a sequence is quadratic based on differences?
  3. How are the coefficients aa, bb, and cc calculated?
  4. Can you describe the significance of constant second differences?
  5. What is the method to verify the simplified sequence formula?

Tip:

Remember that for quadratic sequences, the second differences are always constant and directly relate to the coefficient aa in the general form an2+bn+can^2 + bn + c.

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Math Problem Analysis

Mathematical Concepts

Quadratic Sequences
Arithmetic Sequences
Second Differences

Formulas

General quadratic polynomial sequence formula

Theorems

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Suitable Grade Level

Grades 10-12