Math Problem Statement

Simplify each of the following, expressing the answer using positive indices: (image contains algebraic expressions with square roots, cube roots, and fractional exponents).

Solution

Let's solve the problem step by step, simplifying each expression using positive indices. The goal is to express everything with positive exponents.

(a) x3×x23\sqrt{x^3} \times \sqrt[3]{x^2}

  • Convert to exponential form:

    • x3=x3/2\sqrt{x^3} = x^{3/2}
    • x23=x2/3\sqrt[3]{x^2} = x^{2/3}
  • Multiply the terms: x3/2×x2/3=x(3/2+2/3)x^{3/2} \times x^{2/3} = x^{(3/2 + 2/3)} Find a common denominator for 32\frac{3}{2} and 23\frac{2}{3}, which is 6: 32=96,23=46\frac{3}{2} = \frac{9}{6}, \quad \frac{2}{3} = \frac{4}{6} Now, add: x96+46=x136x^{\frac{9}{6} + \frac{4}{6}} = x^{\frac{13}{6}}

(b) xy3×xy\sqrt[3]{xy} \times \sqrt{xy}

  • Convert to exponential form:

    • xy3=(xy)1/3\sqrt[3]{xy} = (xy)^{1/3}
    • xy=(xy)1/2\sqrt{xy} = (xy)^{1/2}
  • Multiply the terms: (xy)1/3×(xy)1/2=(xy)(1/3+1/2)(xy)^{1/3} \times (xy)^{1/2} = (xy)^{(1/3 + 1/2)} Find a common denominator for 13\frac{1}{3} and 12\frac{1}{2}, which is 6: 13=26,12=36\frac{1}{3} = \frac{2}{6}, \quad \frac{1}{2} = \frac{3}{6} Now, add: (xy)26+36=(xy)56(xy)^{\frac{2}{6} + \frac{3}{6}} = (xy)^{\frac{5}{6}}

(c) xx×x3\frac{\sqrt{x}}{x} \times \sqrt[3]{x}

  • Convert to exponential form:

    • x=x1/2\sqrt{x} = x^{1/2}
    • x3=x1/3\sqrt[3]{x} = x^{1/3}
    • xx=x1/2x=x1/21=x1/2\frac{\sqrt{x}}{x} = \frac{x^{1/2}}{x} = x^{1/2 - 1} = x^{-1/2}
  • Multiply the terms: x1/2×x1/3=x(1/2+1/3)x^{-1/2} \times x^{1/3} = x^{(-1/2 + 1/3)} Find a common denominator for 12-\frac{1}{2} and 13\frac{1}{3}, which is 6: 12=36,13=26-\frac{1}{2} = -\frac{3}{6}, \quad \frac{1}{3} = \frac{2}{6} Now, add: x36+26=x16x^{-\frac{3}{6} + \frac{2}{6}} = x^{-\frac{1}{6}}

(d) xx3×x\frac{x}{\sqrt[3]{x}} \times \sqrt{x}

  • Convert to exponential form:

    • xx3=x1x1/3=x11/3=x2/3\frac{x}{\sqrt[3]{x}} = \frac{x^1}{x^{1/3}} = x^{1 - 1/3} = x^{2/3}
    • x=x1/2\sqrt{x} = x^{1/2}
  • Multiply the terms: x2/3×x1/2=x(2/3+1/2)x^{2/3} \times x^{1/2} = x^{(2/3 + 1/2)} Find a common denominator for 23\frac{2}{3} and 12\frac{1}{2}, which is 6: 23=46,12=36\frac{2}{3} = \frac{4}{6}, \quad \frac{1}{2} = \frac{3}{6} Now, add: x46+36=x76x^{\frac{4}{6} + \frac{3}{6}} = x^{\frac{7}{6}}


Let me know if you'd like more details on the remaining parts (e)-(h), or if you have any questions so far. Here are some follow-up questions:

  1. How do we determine the common denominator when adding fractions?
  2. What is the difference between a square root and a cube root in terms of exponents?
  3. How does simplifying fractional exponents help in simplifying expressions?
  4. Why do we express square roots as powers of 12\frac{1}{2}?
  5. How can we verify the final expressions using exponent rules?

Tip: Always convert roots to fractional exponents first when simplifying expressions involving radicals. This makes applying exponent rules much easier.

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Math Problem Analysis

Mathematical Concepts

Algebra
Exponents
Radicals
Fractional Exponents

Formulas

√x = x^(1/2)
³√x = x^(1/3)
Multiplication of exponents: x^a * x^b = x^(a+b)
Division of exponents: x^a / x^b = x^(a-b)

Theorems

Laws of Exponents
Simplifying Radicals

Suitable Grade Level

Grades 10-12