Math Problem Statement

Simplify the expression: y = (sqrt(x) + x) / x^2

Solution

The given expression is:

y=x+xx2y = \frac{\sqrt{x} + x}{x^2}

Let's simplify this step by step.

Step 1: Separate the terms

We can split the expression into two parts by separating the numerator: y=xx2+xx2y = \frac{\sqrt{x}}{x^2} + \frac{x}{x^2}

Step 2: Simplify each term

  1. For the first term: xx2=x1/2x2=x1/22=x3/2\frac{\sqrt{x}}{x^2} = \frac{x^{1/2}}{x^2} = x^{1/2 - 2} = x^{-3/2}

  2. For the second term: xx2=x1x2=x12=x1\frac{x}{x^2} = \frac{x^1}{x^2} = x^{1-2} = x^{-1}

Step 3: Combine the results

Now, we can rewrite yy as: y=x3/2+x1y = x^{-3/2} + x^{-1}

This is the simplified form of the given expression.

Would you like more details or have any further questions? Here are some related questions you might find helpful:

  1. How do we differentiate the simplified expression y=x3/2+x1y = x^{-3/2} + x^{-1}?
  2. What is the domain of the original function?
  3. How do we find the critical points of the function y=x+xx2y = \frac{\sqrt{x} + x}{x^2}?
  4. How does the original function behave as xx \to \infty and x0+x \to 0^+?
  5. What happens if you change the power of xx in the numerator?

Tip: When simplifying expressions with roots and powers, it's often helpful to convert everything into exponents to make the process smoother.

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Math Problem Analysis

Mathematical Concepts

Algebra
Exponents
Fraction Simplification

Formulas

Exponent rule: x^a / x^b = x^(a-b)
Square root as an exponent: sqrt(x) = x^(1/2)

Theorems

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Suitable Grade Level

Grades 9-11