Let's simplify the given expression step by step:

The expression is:

\[
\frac{s(s+1)(s+2)}{3} + \frac{3(s+1)(s+2)}{3}
\]

1. **Factor out the common terms**: Notice that \((s+1)(s+2)\) is a common factor in both terms.

\[
= \frac{(s(s+1)(s+2) + 3(s+1)(s+2))}{3}
\]

2. **Combine the terms**: Factor out \((s+1)(s+2)\) from the numerator:

\[
= \frac{(s + 3)(s+1)(s+2)}{3}
\]

So the simplified form of the expression is:

\[
\frac{(s + 3)(s+1)(s+2)}{3}
\]

This is the most simplified form of the given expression.

Would you like more details, or do you have any questions?

Here are 5 related questions you might be interested in:

1. How do you factor trinomials?
2. What is the distributive property in algebra?
3. How do you simplify expressions with common factors?
4. How can you factor expressions with three terms?
5. What is polynomial division, and how is it applied?

**Tip:** When simplifying algebraic expressions, always look for common factors to factor out, as it can often simplify the process significantly.

Learn how to simplify the expression (s(s+1)(s+2))/3 + (3(s+1)(s+2))/3 step-by-step. This problem involves algebraic factorization and polynomial simplification techniques. Suitable for high school students in Grades 9-12.

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