Math Problem Statement

Evaluate/simplify the following showing some steps. In other words, ( ( 100 + ( 14 + 6 ) 2 ) / 50 − 8 + 14 / 2 ) / 3 − 3

Solution

Let's break down the given expression step-by-step:

((100+(14+6)2)508+142)/33\left( \frac{ \left( 100 + \left( 14 + 6 \right)^2 \right) }{50} - 8 + \frac{14}{2} \right) / 3 - 3

Step 1: Simplify the inner parentheses

14+6=2014 + 6 = 20 So the expression becomes: ((100+202)508+142)/33\left( \frac{ \left( 100 + 20^2 \right) }{50} - 8 + \frac{14}{2} \right) / 3 - 3

Step 2: Simplify 20220^2

202=40020^2 = 400 Now the expression is: ((100+400)508+142)/33\left( \frac{ \left( 100 + 400 \right) }{50} - 8 + \frac{14}{2} \right) / 3 - 3

Step 3: Simplify inside the parentheses

100+400=500100 + 400 = 500 Now it becomes: (500508+142)/33\left( \frac{500}{50} - 8 + \frac{14}{2} \right) / 3 - 3

Step 4: Divide 500 by 50

50050=10\frac{500}{50} = 10 So the expression becomes: (108+142)/33\left( 10 - 8 + \frac{14}{2} \right) / 3 - 3

Step 5: Simplify 142\frac{14}{2}

142=7\frac{14}{2} = 7 Now we have: (108+7)/33\left( 10 - 8 + 7 \right) / 3 - 3

Step 6: Simplify inside the parentheses

108+7=910 - 8 + 7 = 9 So the expression is: 933\frac{9}{3} - 3

Step 7: Divide 9 by 3

93=3\frac{9}{3} = 3 Now we have: 333 - 3

Step 8: Subtract

33=03 - 3 = 0

So, the simplified result of the expression is:

0\boxed{0}

Would you like a further breakdown or have any questions on this? Here are some additional questions you might find helpful:

  1. How would the result change if the division by 50 happened first?
  2. What is the order of operations (PEMDAS) that guided this simplification?
  3. How can we handle exponents in similar expressions with more terms?
  4. What if we substituted different numbers inside the parentheses—how would that affect the outcome?
  5. What is the importance of simplifying expressions step-by-step in algebra?

Tip: Always remember to simplify inside the innermost parentheses first and follow the order of operations (PEMDAS) to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Order of Operations
Exponents
Algebra

Formulas

PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction)

Theorems

PEMDAS theorem

Suitable Grade Level

Grades 6-8