Let's solve the given expression step by step:

Problem:

$\frac{(x-a)^{-2}}{(x-a)^{-4}} \cdot (x-a)^0 = (x-a)?$

Step 1: Simplify the fraction

Using the property of exponents $\frac{a^m}{a^n} = a^{m-n}$: $\frac{(x-a)^{-2}}{(x-a)^{-4}} = (x-a)^{-2 - (-4)} = (x-a)^{-2 + 4} = (x-a)^2.$

Step 2: Multiply with $(x-a)^0$

The property of exponents states that $a^0 = 1$ (for $a \neq 0$). Hence: $(x-a)^2 \cdot (x-a)^0 = (x-a)^2 \cdot 1 = (x-a)^2.$

Step 3: Check the right-hand side

The given expression simplifies to: $(x-a)^2 = (x-a)?$

Conclusion:

The exponent on the right-hand side must be $2$. Thus: $(x-a)^2 = (x-a)^2.$

Final Answer:

The given equation is true.