The expression $\frac{1}{i6}$ can be interpreted as:

$\frac{1}{i6} = \frac{1}{6i}$

To simplify this expression, we multiply the numerator and the denominator by $-i$ to remove the imaginary unit from the denominator:

$\frac{1}{6i} = \frac{1 \cdot (-i)}{6i \cdot (-i)} = \frac{-i}{6(-i^2)}$

Since $i^2 = -1$, this becomes:

$\frac{-i}{6(1)} = \frac{-i}{6}$

Thus, the simplified form is:

$\boxed{-\frac{i}{6}}$

Would you like me to explain any step in more detail?

Related Questions:

1. How do you rationalize the denominator when dealing with complex numbers?
2. What is the significance of $i^2 = -1$ in complex number calculations?
3. How do you convert complex numbers from rectangular to polar form?
4. Can you explain how to add and subtract complex numbers?
5. How do you multiply and divide complex numbers in polar form?

Tip: Always remember that multiplying the numerator and denominator by the conjugate or $-i$ can help eliminate $i$ from the denominator.