Math Problem Statement

Simplify the following expression.

(4−7i)(4+7i)

Solution

To simplify the expression (47i)(4+7i)(4 - 7i)(4 + 7i), we can use the difference of squares formula:

(ab)(a+b)=a2b2(a - b)(a + b) = a^2 - b^2

Here, a=4a = 4 and b=7ib = 7i. Applying the formula, we get:

(47i)(4+7i)=42(7i)2(4 - 7i)(4 + 7i) = 4^2 - (7i)^2

First, compute 424^2:

42=164^2 = 16

Next, compute (7i)2(7i)^2:

(7i)2=72i2=49(1)=49(7i)^2 = 7^2 \cdot i^2 = 49 \cdot (-1) = -49

Now, substitute these values back into the expression:

(47i)(4+7i)=16(49)(4 - 7i)(4 + 7i) = 16 - (-49)

Simplify the expression:

16(49)=16+49=6516 - (-49) = 16 + 49 = 65

Therefore, the simplified expression is:

(47i)(4+7i)=65(4 - 7i)(4 + 7i) = 65

Would you like any further details or have any questions?

Further Questions:

  1. How does the difference of squares formula apply to complex numbers?
  2. Can you simplify another expression using the difference of squares?
  3. What is the significance of the imaginary unit ii?
  4. How do you multiply two complex numbers in general?
  5. Can you provide an example where the difference of squares formula doesn't apply?
  6. How can you check the correctness of the simplified result?
  7. What is the geometric interpretation of multiplying complex conjugates?
  8. What happens when you multiply a complex number by its conjugate?

Tip:

When multiplying complex conjugates, remember that the imaginary parts cancel out, resulting in a real number.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Difference of Squares

Formulas

Difference of squares formula: (a - b)(a + b) = a^2 - b^2

Theorems

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Suitable Grade Level

Grades 11-12