Math Problem Statement

Simplify the expression to a + bi form: (12 - 9i)^2

Solution

The given expression is (129i)2(12 - 9i)^2, and you need to simplify it into the form a+bia + bi, where aa and bb are real numbers and ii is the imaginary unit.

To simplify:

  1. Use the formula (xy)2=x22xy+y2(x - y)^2 = x^2 - 2xy + y^2.

    • Here, x=12x = 12 and y=9iy = 9i.
  2. Expand (129i)2(12 - 9i)^2:

(129i)2=1222(12)(9i)+(9i)2(12 - 9i)^2 = 12^2 - 2(12)(9i) + (9i)^2

Now, simplify each term:

  • 122=14412^2 = 144,
  • 2(12)(9i)=216i-2(12)(9i) = -216i,
  • (9i)2=81i2=81(1)=81(9i)^2 = 81i^2 = 81(-1) = -81 (since i2=1i^2 = -1).
  1. Combine these results:

(129i)2=144216i81(12 - 9i)^2 = 144 - 216i - 81

  1. Simplify further:

14481=63144 - 81 = 63

So the simplified expression is:

63216i63 - 216i

Thus, the expression in a+bia + bi form is:

63216i63 - 216i

Would you like further explanation or details on this process?

Here are 5 related questions to expand your understanding:

  1. How do you square a complex number using binomial expansion?
  2. What is the significance of the imaginary unit ii in complex numbers?
  3. How does i2=1i^2 = -1 affect calculations involving complex numbers?
  4. Can you express the product of two complex numbers geometrically?
  5. What are the real and imaginary components of a complex number?

Tip: When squaring complex numbers, always remember that i2=1i^2 = -1, which simplifies the calculation.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Binomial Expansion

Formulas

(x - y)^2 = x^2 - 2xy + y^2
i^2 = -1

Theorems

Properties of Complex Numbers
Square of a Binomial

Suitable Grade Level

Grades 10-12