Find the simple intrest when the p=1200 r= 11% t=$$ 1 $$$$ ^{} $$$$ \frac32 $$$$ \sqrt{\placeholder{}} $$$$ 1 $$Years

The formula to calculate **simple interest (SI)** is:

\[
SI = \frac{P \times R \times T}{100}
\]

Where:
- $ P = 1200 $ is the principal amount,
- $ R = 11\% $ is the rate of interest per annum,
- $ T = 1 \frac{1}{2} = 1.5 $ years is the time period.

### Step 1: Substituting the given values into the formula:

\[
SI = \frac{1200 \times 11 \times 1.5}{100}
\]

### Step 2: Calculating:

\[
SI = \frac{1200 \times 16.5}{100} = \frac{19800}{100} = 198
\]

Thus, the simple interest is **198 units**.

Would you like more details on this or have any questions?

### Here are 5 related questions to explore:
1. How do we calculate the total amount after adding simple interest to the principal?
2. How does simple interest change if the time is doubled?
3. What is the difference between simple interest and compound interest?
4. How does the interest rate affect the simple interest formula?
5. How can we calculate time if the simple interest, principal, and rate are given?

**Tip:** For longer durations or higher interest rates, compound interest gives a significantly larger return compared to simple interest.

Find the simple interest when the principal (P) = 1200, the rate of interest (R) = 11%, and the time (T) = 1.5 years.

Learn how to calculate simple interest using the formula SI = (P × R × T) / 100. This problem involves a principal of 1200, an interest rate of 11%, and a time period of 1.5 years. Step-by-step solution provided. Suitable for students in Grades 6-8.

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