Math Problem Statement

Use the shell method to find the volume of the solid generated by revolving the shaded region about the​ y-axis. y=1+(x^2/4) bounds are 0 and 2 The volume is    enter your response here cubic units. ​(Type an exact answer in terms of pi​.)

Solution

To find the volume of the solid generated by revolving the region bounded by y=1+x24y = 1 + \frac{x^2}{4}, with bounds x=0x = 0 and x=2x = 2, about the y-axis, we can use the shell method.

The shell method formula for volume about the y-axis is:

V=2πabxf(x)dxV = 2\pi \int_{a}^{b} x \cdot f(x) \, dx Where:

  • xx is the radius of a shell.
  • f(x)f(x) is the height of the shell.
  • aa and bb are the limits of integration (in this case, from x=0x = 0 to x=2x = 2).

Step 1: Identify the function and bounds

The given function is: y=1+x24y = 1 + \frac{x^2}{4} We are rotating this about the y-axis, with bounds x=0x = 0 to x=2x = 2.

Thus, f(x)=1+x24f(x) = 1 + \frac{x^2}{4}.

Step 2: Set up the integral using the shell method

We now set up the volume integral: V=2π02x(1+x24)dxV = 2\pi \int_{0}^{2} x \cdot \left( 1 + \frac{x^2}{4} \right) \, dx

Step 3: Solve the integral

Expand the integrand: V=2π02(x+x34)dxV = 2\pi \int_{0}^{2} \left( x + \frac{x^3}{4} \right) \, dx Now, integrate each term separately: 02xdx=x2202=222022=2\int_{0}^{2} x \, dx = \frac{x^2}{2} \Bigg|_0^2 = \frac{2^2}{2} - \frac{0^2}{2} = 2 02x34dx=14x4402=116(2404)=11616=1\int_{0}^{2} \frac{x^3}{4} \, dx = \frac{1}{4} \cdot \frac{x^4}{4} \Bigg|_0^2 = \frac{1}{16} \cdot (2^4 - 0^4) = \frac{1}{16} \cdot 16 = 1

Step 4: Combine the results

Now, substitute the results of the integrals: V=2π(2+1)=2π×3=6πV = 2\pi \left( 2 + 1 \right) = 2\pi \times 3 = 6\pi

Final Answer:

The volume of the solid is 6π\boxed{6\pi} cubic units.


Would you like any further explanation on the shell method or related topics? Here are some related questions you might find interesting:

  1. How does the shell method compare to the disk/washer method in finding volumes?
  2. What if the region is revolved about the x-axis instead of the y-axis?
  3. How do you apply the shell method to solids with different bounds or more complex functions?
  4. What is the physical interpretation of using the shell method for volume?
  5. Can the shell method be used in higher dimensions, and how?

Tip: When using the shell method, it's important to visualize the radius of each cylindrical shell and the height it spans in relation to the axis of rotation.

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Math Problem Analysis

Mathematical Concepts

Calculus
Volume of Solids of Revolution
Shell Method

Formulas

V = 2π ∫ from a to b x * f(x) dx

Theorems

Shell Method for Volume Calculation

Suitable Grade Level

Grades 11-12