Math Problem Statement

What is the area of the shaded region in a figure with a circle inscribed in a square, given the circle has a diameter of 24 meters?

Solution

The problem involves a circle inscribed in a square, and you're asked to find the area of the shaded region between the square and the circle.

Step 1: Circle's Radius and Area

The given diameter of the circle is 24 meters, so the radius rr is: r=242=12mr = \frac{24}{2} = 12 \, \text{m} The area AcircleA_{\text{circle}} of the circle is given by the formula: Acircle=πr2=π(12)2=144πm2A_{\text{circle}} = \pi r^2 = \pi (12)^2 = 144\pi \, \text{m}^2 Approximating π3.1416\pi \approx 3.1416: Acircle144×3.1416=452.39m2A_{\text{circle}} \approx 144 \times 3.1416 = 452.39 \, \text{m}^2

Step 2: Square's Side Length and Area

Since the circle is inscribed, the diameter of the circle is equal to the side length of the square, so the side length ss of the square is: s=24ms = 24 \, \text{m} The area AsquareA_{\text{square}} of the square is: Asquare=s2=242=576m2A_{\text{square}} = s^2 = 24^2 = 576 \, \text{m}^2

Step 3: Shaded Area

The shaded area is the difference between the area of the square and the area of the circle: Ashaded=AsquareAcircle=576452.39=123.61m2A_{\text{shaded}} = A_{\text{square}} - A_{\text{circle}} = 576 - 452.39 = 123.61 \, \text{m}^2 Rounding to the nearest whole number: Ashaded124m2A_{\text{shaded}} \approx 124 \, \text{m}^2

Thus, the area of the shaded region is approximately 124 m².

Would you like any more details or have any questions?

Related Questions:

  1. What is the area of a circle with a diameter of 36 meters?
  2. How would the shaded area change if the diameter of the circle was increased by 50%?
  3. What is the perimeter of the square?
  4. How does the area of the square relate to the diameter of the circle?
  5. How would the problem change if the circle was circumscribed around the square?

Tip: Always remember that for a circle inscribed in a square, the diameter of the circle equals the side length of the square.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of a Circle
Area of a Square
Subtraction of Areas

Formulas

Area of a Circle = πr²
Area of a Square = s²
Shaded Area = Area of Square - Area of Circle

Theorems

Inscribed Circle Theorem

Suitable Grade Level

Grades 7-9